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kiruha [24]
2 years ago
5

Solve this equation: -7.2 + 12 - 2.c

Mathematics
1 answer:
lilavasa [31]2 years ago
7 0

Answer:

4.8-46c+13x

Step-by-step explanation:

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Pls helppp me this is very very urgent
Nat2105 [25]

Answer:

1. 5040

2. 20

Step-by-step explanation:

1. using the formula for permutation

nPr=n!/(n-r)!

10P4 = 10!/(10-4)!

=10*9*8*7*6!/6!

then we are left with

=10*9*8*7

=5040

2.using the formula for combination

nCr=n!/(n-r)!r!

6C3=6!/(6-3)!3!

=6*5*4*3!/3!3!

=6*5*4/3*2*1

=20

4 0
3 years ago
The table shows the battery life of four different mobile phones:
tekilochka [14]
Answer: Phone C

Using quick mental math, we can do 8% of 10 to get 0.8, which is close to the value of 0.0845*10. Also fairly quick is moving the decimal point over 1 spot to the right and we go from 0.0845 to 0.845 and that rounds to 0.8 when rounding to one decimal place. Recall that 8.45% = (8.45/100) = 0.0845

If you want to compute out the four results with a calculator, then it would look like this:
0.0845*20 = 1.69
0.0845*25 = 2.1125
0.0845*10 = 0.845
0.0845*18 = 1.521
and this shows that no other result (but choice C) is close to 0.8

So that's why the answer is choice C
5 0
2 years ago
Read 2 more answers
Which statements are true for the following expression? (9 + 3) · 4
ss7ja [257]

Answer:

12 x 4   or  48

Step-by-step explanation:

6 0
3 years ago
the average rate of change of the function f(x) on the interval -3≤x≤3 is -2.5. If (-3)=14 then which of the following is the va
oksian1 [2.3K]

The average rate of change of <em>f(x)</em> on -3 ≤ <em>x</em> ≤ 3 is given to be

(<em>f</em> (3) - <em>f</em> (-3)) / (3 - (-3)) = -2.5

If <em>f</em> (-3) = 14, then

(<em>f</em> (3) - 14) / (3 + 3) = -2.5

(<em>f</em> (3) - 14) / 6 = -2.5

<em>f</em> (3) - 14 = -15

<em>f</em> (3) = -1

4 0
3 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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