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kiruha [24]
2 years ago
5

Solve this equation: -7.2 + 12 - 2.c

Mathematics
1 answer:
lilavasa [31]2 years ago
7 0

Answer:

4.8-46c+13x

Step-by-step explanation:

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Write the equation of the line in slope-intercept form using y=mx+b​
victus00 [196]

The slope is given as m = 7m=7 and the yy-intercept as b = - \,4b=−4. Substituting into the slope-intercept formula y = mx + by=mx+b, we have

since m=7 and b=-4, we can substitute that into the slope-intercept form of a line to get y=mx+b → y=7x-4

The slope is positive thus the line is increasing or rising from left to right, but passing through the yy-axis at point \left( {0, - \,4} \right)(0,−4).

Step-by-step explanation:

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Students are getting signatures for a petition to increase sports activities at the comunitu center. The number of signatures th
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In Need of help please Help :c
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Answer:

  • proportional: A, B, D, G, I
  • non-proportional: C, E, F, H

Step-by-step explanation:

Any relation with a non-zero initial value or y-intercept is non-proportional. Any relation that has a constant ratio between output and input is proportional.

  C has an initial value of 7

  E has a y-intercept of -3

  F has an initial value of 2.00

  H has an initial value of 5

All of these are non-proportional. The remainder are proportional.

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Gavin is working on an animated film about skiing. The figure shows a ski slope, represented by AB←→, and one of the chairs on t
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3 years ago
What value of x is in the solution set of 9(2x + 1) < 9x – 18
netineya [11]
The answer is:  " x < -3 " .
_____________________
Explanation:
_____________________
Given:
______________________
  " 9(2x + 1) < 9x – 18 " ;

First , factor out a "9" in the expression on the right-hand side of the inequality:

9x – 18 = 9(x – 2) ;

and rewrite the inequality:
_____________________
9(2x + 1) < 9(x – 2) ;

Now, divide EACH SIDE of the inequality by "9" ;

[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;

to get:

2x + 1 < x – 2 ; 

Now, subtract "x" and add "2" to each side of the inequality:

2x + 1 – x + 2  <  x – 2  – x + 2 ;

to get:

x + 3 < 0 ;

Subtract "3" from EACH SIDE ;

x + 3 – 3 < 0 – 3 ;

to get:

      " x < -3 "  .
____________________________________
8 0
3 years ago
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