Question

A man gave out 24000 to his three brothers,X ,Y and Z to be shared among them . If X takes twice as much as Y and Y is given one-third of what Z takes how much did each of them receive?

Answer 1

The amount received by each of the three brothers from the $24,000 given them based on their sharing ratios is worked out using a system of equations as follows:

X' share = $8,000

Y's share = $4,000

Z's share = $12,000

What is an equation?

An equation is a mathematical statement that shows that two values are equal.

A system of equations uses numbers and variables.

Data and Calculations:

Amount to be shared = $24,000

Sharers = X ,Y and Z

Sharing ratios:

X takes twice as Y = 2y

Y takes 1/3 of Z, Y = y

Z receives 1/3 of Y = 3y

Ratio = 2y + y + 3y

2y + y + 3y = 24,000

6y = 24,000

y = 4,000

X' share = $8,000 (2 x 4,000)

Y's share = $4,000 (4,000)

Z's share = $12,000 (3 x 4,000)

Thus, from the $24,000, X received $8,000, which is twice as much as Y's $4,000, and Y's share is one-third of Z's $12,000.

Learn more about equations at brainly.com/question/2972832

#SPJ1