All categories

1 year ago

Please help this is due ❗️❗️❗️❗️❗️

Mathematics

2 answers:

aleksandr82 [10.1K]1 year ago

8 0

Answer:

Step-by-step explanation:

$19x^2y-4xy^2+5xy^2-16x^2y=\\3x^2y+xy^2=\\xy*(3x+y)$

Nady [450]1 year ago

6 0

19x^2y-4xy^2+5xy^2-16x^2y
write the similar terms together
19x^2y-16x^2y-4xy^2+5xy^2
3x^2y+xy^2 is the answer

You might be interested in

How does the rate of change vary from point to point?

Tpy6a [65]

$\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 40&32\\ 28&16\\ 16&12\\ \cline{1-2} \end{array}~\hfill \stackrel{\textit{average rate of change}}{slope} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{40}~,~\stackrel{y_1}{32})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-32}{28-40}\implies \cfrac{-16}{-12}\implies \boxed{\cfrac{4}{3}} \\\\[-0.35em] ~\dotfill$

$\bf (\stackrel{x_1}{28}~,~\stackrel{y_1}{16})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-16}{16-28}\implies \cfrac{-4}{-12}\implies \boxed{\cfrac{1}{3}}$

8 0

2 years ago

To avoid modeling the physical characteristics of wheel encoders such the square wave outputs, it is desirable to generate encod

grandymaker [24]

Answer:

The probability distribution is Normal continuous

Step-by-step explanation:

The basic idea is that velocity values have different noise level and an important thing regarding continuous probability distributions is that the probability of the random variable is equal to a specific outcome is 0

In other words, is practically impossible that one value of velocity could be the same as others.

5 0

2 years ago

Kaytaytay talk here

DochEvi [55]

Integers I believe :) hope this helps

5 0

1 year ago

Someone should really help me....

NikAS [45]

Answer:

Polynomial

Step-by-step explanation:

3 0

2 years ago

g A program executes a mix of different instruction types. 25% of the instructions require two clock cycles to execute, 20% requ

Tomtit [17]

Answer:

1.8 cycles

Step-by-step explanation:

The average number of clock cycles per instruction is given by the sum of the product of each possible number of cycles by its likelihood.

1 cycle: 50%

2 cycles : 25%

3 cycles : 20%

4 cycles : 5%

$Avg = 0.5*1+0.25*2+0.20*3+0.05*4\\Avg= 1.8\ cycles$

The average number of clock cycles per instruction is 1.8.

8 0

2 years ago