1 year ago

Please help this is due ❗️❗️❗️❗️❗️

2 answers:

8 0

Answer:

Step-by-step explanation:

$19x^2y-4xy^2+5xy^2-16x^2y=\\3x^2y+xy^2=\\xy*(3x+y)$

6 0

19x^2y-4xy^2+5xy^2-16x^2y
write the similar terms together
19x^2y-16x^2y-4xy^2+5xy^2
3x^2y+xy^2 is the answer

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arlik [135]

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = $\sqrt{1-cos^2x}$

Note that ( $\frac{4\sqrt{2} }{7}$ )² = $\frac{32}{49}$

sinΘ = $\sqrt{1-(32/49)}$

= $\sqrt{\frac{17}{49} }$ = $\frac{\sqrt{17} }{7}$

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Ronch [10]

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WARRIOR [948]

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Step-by-step explanation:

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777dan777 [17]

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