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timurjin [86]
4 years ago
6

Complete the steps to factor the polynomial by grouping.P(x) = x3 + 5x2 – x – 5

Mathematics
2 answers:
ahrayia [7]4 years ago
6 0
<span>P(x) = x</span>³<span> + 5x</span>²<span> – x – 5

P(x) = x</span>²(x+5) - (x + 5)

P(x) = (x + 5)(x² - 1)

P(x) = (x + 5) (x + 1)(x -1)
valentina_108 [34]4 years ago
6 0

Answer

Find the  steps to factor the polynomial by grouping.

To prove

As given the polynomial in the question

P(x) = x³ + 5x² – x – 5

P(x) = x² (x + 5) – (x + 5)

Take  (x + 5) as common

P(x) =  (x + 5) (x² - 1)

As using the identity

(a² - b²) = (a - b)(a + b)

P(x) =  (x + 5) (x - 1)(x + 1)

Therefore the factors of the polynomial by grouping are (x + 5) and (x - 1)(x + 1) .

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Read 2 more answers
What is the solution to the system of equations?<br> Y=2x-3.5<br> X-2y=-14
GuDViN [60]
( 7, 10.5 )

<em>Solution:
</em><em />
y = 2x - 3.5
x - 2 y = -14

Plug the first equation into the second equation like so;
x - 2 ( 2x - 3.5 ) = -14
Distribute -2 to 2x and -3.5

Your equation should now look like this:

x - 4x + 7 =  -14
You want common numbers to be in the same side so you subtract 7 from both sides

x - 4x + 7 - 7 =  -7 - 14

Now simplify both sides

x - 4x = -3x
- 7 - 14 = -21

In order to solve for x you need to get x by itself, so you divide both sides by -3

-3x / -3 = x
-21 / -3 = 7
x = 7

In order to solve for y you need to plug x in
(You can plug it into either equation, but I'm plugging it into the first one)

y = 2 (7) - 3.5
y = 14 - 3.5
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