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Ksivusya [100]
2 years ago
9

What are benefits of AI

Computers and Technology
2 answers:
baherus [9]2 years ago
8 0

Answer:

smarter and more advanced learning

Explanation:

navik [9.2K]2 years ago
7 0
Reduction in human error. Unbiased decisions. Being able to do repetitive tasks
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1) In your own words, explain what a browser is. 2) Why is it important to keep your browser up to date?
marta [7]

Answer:

A browser is a software that is used to access the internet. A browser lets you visit websites and do activities within them like login, view multimedia, link from one site to another, visit one page from another, print, send and receive emails, among many other activities

The most important reason to keep your browser up-to-date is for your own safety and security, and that of your computer. ... If you're a Firefox user, your browser will remind you to update your add-ons whenever new versions become available.

Malicious hackers and Web sites can exploit security flaws in browsers and infect your computer with harmful programs, trojans, and viruses. Regular updates to your browser fix security problems when they are detected, and make your computer safer from those types of attacks.

6 0
4 years ago
Write a program with total change amount as an integer input that outputs the change using the fewest coins, one coin type per l
sweet [91]

Answer:

#include<stdio.h>

#define DOLLAR 100

#define QUARTER 25

#define DIME 10

#define NICKEL 5

#define PENNY 1

void calculatedChange(int userAmount,int coinValues[])

{

if (userAmount >=100)

{

coinValues[0]=userAmount/DOLLAR;

userAmount=userAmount-(100*coinValues[0]);

}

if (userAmount >=25)

{

coinValues[1]=userAmount/QUARTER;

userAmount=userAmount-(25*coinValues[1] );  

}

if (userAmount >=10)

{

coinValues[2]=userAmount/DIME;

userAmount=userAmount-(10*coinValues[2]);

}

if (userAmount >=5)

{  

coinValues[3]=userAmount/NICKEL;

userAmount=userAmount-(5*coinValues[3]);

}

if (userAmount >=1)

{

coinValues[4]=userAmount/PENNY;

userAmount=userAmount-coinValues[4];

}

}

int main() {

int amount;

printf("Enter the amount in cents :");

scanf("%d",&amount);

if(amount<1)

{

printf("No change..!");

}

else

{

int coinValues[5]={0,0,0,0,0};

calculatedChange(amount,coinValues);

if (coinValues[0]>0)

{

printf("%d Dollar",coinValues[0]);

if(coinValues[0]>1) printf("s");

}

if (coinValues[1]>0)

{

printf(" %d Quarter",coinValues[1]);

if(coinValues[1]>1) printf("s");

}

if (coinValues[2]>0)

{

printf(" %d Dime",coinValues[2]);

if(coinValues[2]>1) printf("s");

}

if (coinValues[3]>0)

{

printf(" %d Nickel",coinValues[3]);

if(coinValues[3]>1) printf("s");

}

if (coinValues[4]>0)

{

printf(" %d Penn",coinValues[4]);

if(coinValues[4]>1) printf("ies");

else printf("y");

}

}

}

Explanation:

  • Create a calculatedChange method for calculating userAmount.  
  • Use conditional statements to check dollars , quarters , dimes , nickels  and penny.
  • Inside the main method , validate the input  and then  print dollars , dimes , nickels after checking them.

7 0
3 years ago
The advancement in speed of transportation is attributed to invention of this device
morpeh [17]
The automobile is the invention
3 0
3 years ago
NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

3 0
3 years ago
A 10 Superscript negative 910−9​-F capacitor ​(11 nanofaradnanofarad​) is charged to 5050 V and then disconnected. One can model
vredina [299]

Answer:

Explanation:

i) On a cold day, Capacity = (66 X 910 X 10∧-9) F

Charge, Q = (66 X 910 X 10∧-9) X 5050 = 0.30 Columb

Current, I= 5050/131013 = 0.039 Amp (where Resistance = 131013 ohms)

Time, t= 0.30/0.039 = 7.7 seconds

ii) On a humid day, Capacity = (77 X 910 X 10∧-9) F

Charge, Q = ( 77 X 910 X 10∧-9) X 5050 = 0.35 Columb

Current, I= 5050/6106 = 0.83 Amp ( where Resistance = 6106 ohms)

Time, t= 0.35/0.83 = 0.42 h or  0.42 X 60 mins = 25 mins

7 0
3 years ago
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