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Alenkasestr [34]
3 years ago
14

Which of the following is NOT a Boolean Search term used to refine search engine results? A. AND B. With C. OR D. NOT

Computers and Technology
2 answers:
den301095 [7]3 years ago
7 0
B. With. Width isn't a boolean comparative operator
gayaneshka [121]3 years ago
7 0

Answer:

The correct answer to the following question is option B. With.

Explanation:

Because With is not the Boolean operator.

Boolean words are the simple words that are used to combine or to exclude keywords in resulting and search in more productive and focused results.

Boolean operators are:

  • AND
  • OR
  • NOT
  • AND NOT
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telo118 [61]
D. 2^3 is correct

hope this helps

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3 years ago
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Is a defense of a political position an argument
shutvik [7]

Answer:

yes

Explanation:

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Which windows system include new features and extends the functionality
Juli2301 [7.4K]

Critical update

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3 years ago
Why might a variable used for output have to be of a different type then a variable used for input?​
telo118 [61]

Answer:

You may use a different variable type for input in order to process the data appropriately and may use a different variable type to accommodate your program.

Explanation:

Your input may have to be different then output varying on what data you are processing.

For example, just like the last question you asked about calculating the area of the rectangle, your input MUST be converted to a different a numerical data type (i.e int or float) in order to do the math.

Based on your last question, if we didn't convert your input into a string your results wouldn't add the numbers together but only concatenate them. If I typed 3 & 5 as length & width, I would get 35 instead of 15.

Now another example is using functions (or methods whatever you want to call them), your input can be one thing and outputs another.

Let's say I want a function to tell me if I am smart. The way I want it to determine if its smart is by inputting my GPA into it, which is a numerical value. So the function would look something like this:

<u>Code (Python)</u>

def IsSmart(gpa):

  if (gpa >= 4):

       return True

  else

       return False

As you can see I am inputting a numerical value and it is outputting a boolean value. I can use this in a if else chain to spit out an output to the user.

7 0
3 years ago
If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
Molodets [167]

Answer:

Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0
3 years ago
Read 2 more answers
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