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Levart [38]
1 year ago
11

Identify the angle relationship. Then find solve the value

Mathematics
1 answer:
Licemer1 [7]1 year ago
8 0

Answer:

Hi!

296+34+b=360

330+b=360

b=360-330

b=30°



God work.

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Can you help with this?
g100num [7]

Answer:

c or d

Step-by-step explanation:

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8 0
3 years ago
what is the mistake in this problem and why is it wrong? 15+(√9•7)÷13 = 15+(3•7)÷3 = 15+(21)÷3 = 36+3 =12
Serggg [28]

[Edit:}

Okay! So after you have 15+(21)÷3, you have to remember PEMDAS.

PEMDAS is the order in which you solve equations.

1. Parentheses: you solve everything in the parentheses first, all while following the rules of PEMDAS

2. Exponents: after you solve the things in the parentheses, you do the exponents.

3. Then you do Multiplication or Division, solving in the order from left to right.

4. After, you do Addition or Subtraction, solving in the order from left to right.

So using PEMDAS, we'll solve 15+(21)÷3.

We do division before addition, so 21/3 is 7.

Then you add 15 to 7 and get 22 as your final answer.

Hope this helps!

7 0
3 years ago
Which is the least ...0.105 0.501 0.015 0.15
sergeinik [125]
The least is 0,015

hope this will help you 
3 0
3 years ago
Read 2 more answers
The width of a rectangle is the sum of the length and 1. The area of the rectangle is 20 units. What is the width, in units, of
IRISSAK [1]

Answer:

W=5

Step-by-step explanation:

W=Width=Length + 1

L = Length

Area = Length * Width = 20

Area = L * W = L * (L+1) = 20

Distribute the L:   L^2 + L = 20

Subtract 20 from both sides: L^2 + L -20 = 20-20

Simplify:  L^2+L-20=0

Factor (L-4)(L+5)=0

Solve using the zero property: L-4=0, L=4      L+5=0, L=-5

The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative.   Width is Length + 1 = 5

6 0
3 years ago
Evaulate the function at the indicated values h(t)=t+(3/t)i find h(x-1)
alex41 [277]

<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>

Note that the domain of h is <span>[0,∞]</span>.

By differentiating,

<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>

by factoring out <span>34</span>,

<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>

by finding the common denominator,

<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>

<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>

Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.

Hence, the critical numbers are <span>t=0,1</span>.

I hope that this was helpful.

6 0
3 years ago
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