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kari74 [83]
3 years ago
15

How to solve 6x^2+5x-4=0

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
6x^2+5x-4=0\\\\6x^2+8x-3x-4\\\\2x(3x+4)-1(3x+4)=0\\\\(3x+4)(2x-1)=0\iff3x+4=0\ or\ 2x-1=0\\\\3x=-4\ or\ 2x=1\\\\\boxed{x=-\frac{4}{3}\ or\ x=\frac{1}{2}}

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