How to solve 6x^2+5x-4=0

Mathematics

1 answer:

Vesna [10]3 years ago

6 0

$6x^2+5x-4=0\\\\6x^2+8x-3x-4\\\\2x(3x+4)-1(3x+4)=0\\\\(3x+4)(2x-1)=0\iff3x+4=0\ or\ 2x-1=0\\\\3x=-4\ or\ 2x=1\\\\\boxed{x=-\frac{4}{3}\ or\ x=\frac{1}{2}}$

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