3 years ago

How to solve 6x^2+5x-4=0

1 answer:

6 0

$6x^2+5x-4=0\\\\6x^2+8x-3x-4\\\\2x(3x+4)-1(3x+4)=0\\\\(3x+4)(2x-1)=0\iff3x+4=0\ or\ 2x-1=0\\\\3x=-4\ or\ 2x=1\\\\\boxed{x=-\frac{4}{3}\ or\ x=\frac{1}{2}}$

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The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.

babunello [35]

The x-coordinate of the given endpoint will be " $x = 4 \pm 2\sqrt{29}$ ".

According to the question,

The end points are:

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Distance,

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As we know,

The distance formula,

→ $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By substituting the values, we get

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→ $216= (x-4)^2+100$

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→ $x-4 = \pm \sqrt{116}$

→ $x-4=\pm 2\sqrt{29}$

→ $x = 4 \pm 2\sqrt{29}$

Thus the above answer is right.

Learn more:

brainly.com/question/18310956

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2 years ago

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Step-by-step explanation:

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Divide $107.60 by 8

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