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Darina [25.2K]
3 years ago
12

The area of a circle is 113.04in^2. what is the radius of the circle

Mathematics
1 answer:
Alex3 years ago
5 0

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} A=113.04 \end{cases}\implies 113.04=\pi r^2\implies \cfrac{113.04}{\pi }=r^2 \\\\\\ \stackrel{using~\pi =3.14}{36}=r^2\implies \sqrt{36}=r\implies 6=r

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An art teacher has a roll of mural paper that is 5 meters long.
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6 0
2 years ago
PLEASE HELP! Thank you!
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3 years ago
The library has DVDs on crime, adventure and science fiction.
kozerog [31]

Answer:

The library has 1,056 crime DVDs.

Step-by-step explanatiion:

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384=4x

x=96

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6 0
2 years ago
Mr. and Mrs. Rainer took out a $240,000 loan to purchase their home. If the interest rate on the loan is 1.2% compounded bimonth
Bogdan [553]

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Number of times in an year = 24

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6 0
3 years ago
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

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Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
2 years ago
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