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alisha [4.7K]
3 years ago
12

There are two different compounds of sulfur and fluorine. In SF6, the mass of fluorine per gram of sulfur is 3.55 g F/g S. In th

e other compound, SFX, the mass of fluorine per gram of sulfur is 1.18 g F/g S. What is the value of X for the second compound
Chemistry
1 answer:
irinina [24]3 years ago
6 0
For the answer to the question above, <span>1.18 x 3 = 3.55.</span>
<span>First, you need to find the ratio of F to F in each compound. It is the law of multiple proportions stating that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers. In this case, F would be the "one element" and S would be the "fixed mass", the ratio of F6 to Fx = 3:1 </span>
<span>therefore x would be 2 since there is less F in SFx and the ratio is 3:1. divide 6 by 3 and you get 2.</span>
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A. Clearly draw the Lewis structure for the PBr4- ion. Show your math where
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A first order reaction has 1/16 of the original amount left after 500 seconds. What is the half-life of the reactant in this rea
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A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

<h3>What is a first order reaction?</h3>

It is a chemical reaction in which the rate of reaction is directly proportional to the concentration of the reacting substance.

First, we will calculate the rate constant using the following expression.

ln ([A]/[A]₀) = - k × t

ln (1/16[A]₀/[A]₀) = - k × 500 s

k = 5.55 × 10⁻³ s⁻¹

where,

  • [A] is the final concentration of the reactant.
  • [A]₀ is the initial concentration of the reactant.
  • k is the rate constant.
  • t is the elapsed time.

Next, we can calculate the half-life (th) using the following expression.

th = ln 2 / k = ln 2 / (5.55 × 10⁻³ s⁻¹) = 125 s

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

Learn more about first order reactions here: brainly.com/question/518682

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