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3 years ago

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A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work

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1 answer:

adell [148]3 years ago

7 0

pH of buffer can be calculated as:

pH=pKa+log[salt]/[Acid]

As ka = 4.58 x 10-4

Concentration of [Salt] that is NO2(-1)=0.380M

Concentration of [Acid] that is HNO2=0.500M

So, pH= -log(4.58*10^-4)+log((0.380)/0.500))

=3.21

So pH of solution will be 3.21

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An aqueous solution of 10.03 g of catalase, an enzyme found in the liver, has a volume of 1.05 L at 27°C. The solution's osmotic

-Dominant- [34]

Answer : The molar mass of catalase is, $2.40\times 10^5g/mol$

Explanation :

Formula used :

$\pi =CRT\\\\\pi=\frac{w}{M\times V}RT$

where,

$\pi$ = osmotic pressure = 0.745 torr = 0.000980 atm (1 atm = 760 torr)

C = concentration

R = solution constant = 0.0821 L.atm/mol.K

T = temperature = $27^oC=273+27=300K$

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution = 1.05 L

Now put all the given values in the above formula, we get:

$0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)$

$M=2.40\times 10^5g/mol$

Therefore, the molar mass of catalase is, $2.40\times 10^5g/mol$

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3 years ago

a household’s voltage is 120 volts, what is the power rating of a light bulb with 0.5 amps of current flowing through it?

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3 years ago

Which identifies an oxidation-reduction reaction?

Strike441 [17]

Answer:

Explanation:

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Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

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8 0

3 years ago

Find the celcius equivalent of 133 degrees Kelvin

egoroff_w [7]

Answer:

<h2>406 K</h2>

Explanation:

To convert a temperature from degree Celsius to Kelvin add 273 to the value in degree Celsius

That's

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From the question we have

K = 273 + 133

We have the final answer as

<h3>406 K</h3>

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5 0

3 years ago

Read 2 more answers

A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration

svlad2 [7]

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

C1V1 = C2V2

3 x 185 = C2 x 750

Divide both side by 750

C2 = 3 x 185 / 750

C2 = 0.74M

Therefore, the new concentration of the solution is 0.74M

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3 years ago