pH of buffer can be calculated as:
pH=pKa+log[salt]/[Acid]
As ka = 4.58 x 10-4
Concentration of [Salt] that is NO2(-1)=0.380M
Concentration of [Acid] that is HNO2=0.500M
So, pH= -log(4.58*10^-4)+log((0.380)/0.500))
=3.21
So pH of solution will be 3.21
Answer:
C8H8 + 10O2 → 8CO2 + 4H2O
Explanation:
unbalanced reaction:
C8H8 + O2 → CO2 + H2O
balanced for semireactions:
(1) 16H2O + C8H8 → 8CO2 + 40H+
(2) 10(4H+ + O2 → 2H2O)
⇒ 40H+ + 10O2 → 20H2O
(1) + (2):
balanced reaction:
⇒ C8H8 + 10O2 → 8CO2 + 4H2O
8 - C - 8
20 - O2 - 20
8 - H - 8
look at the picture above
