A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work
.
1 answer:
pH of buffer can be calculated as:
pH=pKa+log[salt]/[Acid]
As ka = 4.58 x 10-4
Concentration of [Salt] that is NO2(-1)=0.380M
Concentration of [Acid] that is HNO2=0.500M
So, pH= -log(4.58*10^-4)+log((0.380)/0.500))
=3.21
So pH of solution will be 3.21
You might be interested in
Answer: Option A. 6.022 x 10^23
Explanation:
Answer:
a simple voltaic cell is made by immersing one zinc plate and one copper plate inside water diluted sulfuric acid solution.
All of these are compounds except oxygen because a compound is two or more different elements bonded together.
Give the positional isomers of 2 halopropane
(CH3)2CH
answer:
is in file download it
Answer:
Explanation:
Polar molecules interact with other molecules of similar polarity to form solutions. Non-polar molecules do not interact the same way.
