DR is the correct answer
hope this helps
The dependant variable is what you measure during the experiment and what is affected in the experiment (this is for question 4) so the answer would be D
Answer: About 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture
You may find bellow the balanced chemical equations.
Explanation:
Molecular equations:
3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)
2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)
Ionic equations:
3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)
2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)
To get the net ionic equation we remove the spectator ions:
3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s)
2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)
Learn more about:
net ionic equations
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