2 years ago

Someone do this for me please

Mathematics

1 answer:

iVinArrow [24]2 years ago

8 0

Answer:

2+7895 hfcygshcrnagdjdhxr

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steposvetlana [31]

Answer: $11.45

Step-by-step explanation:

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Tax: 6%

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4 years ago

50 POINTS PLEASE HELP!!!!!!!!!! ALL SH!+Y ANSWERS REPORTED.

NNADVOKAT [17]

62=14 + 2x

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3 years ago

The sum of two squares of two consecutive natural numbers is 41.Find the numbers

Arada [10]

<h3><u>AnswEr</u><u> </u><u>:</u></h3>

The 2 unknown numbers are 4 and 5 .

<h3><u>Expla</u><u>nation</u><u> </u><u>:</u></h3>

Let the numbers be x and x + 1.

From the given information,

$\dashrightarrow\sf \ \ \ x^2 + (x + 1)^2 = 41 \\ \\ \\$

$\dashrightarrow\sf \ \ \ 2 {x}^{2} + 2x + 1 = 41 \\ \\ \\$

$\dashrightarrow\sf \ \ \ 2 {x}^{2} + 2x + 1 - 41=0 \\ \\ \\$

$\dashrightarrow\sf \ \ \ {x}^{2} + x - 20 = 0 \\ \\ \\$

$\dashrightarrow\sf \ \ \ (x + 5)(x - 4)=0 \\ \\ \\$

$\dashrightarrow\sf \ \ \ { \underline{ \boxed{ \bf{ \red{x = - 5,4}}}}} \ \bigstar \\ \\$

But, as we know -5 is not a natural number,

Hence, x = 4 .

<u>So the 2 unknown numbers are</u><u> </u><u>:</u>

x = 4 [1st number]

x + 1 = 4 + 1 = 5 [2nd number]

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