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jeka94
2 years ago
10

Write the equation of a line that is perpendicular to y = -2/3x + 1 and passes through (-6 , 4 ).

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Answer:

So your answer is x=0.

Step-by-step explanation:

You might be interested in
What is the equation for the line
Pavel [41]
The model equation for any line is
y = mx + b,
where m is slope and b is y-intercept (where the line intersects the y-axis).

The slope is change in y over change in x. You can find the slope by picking two points. The numerator will be the difference in y-coordinates, and the denominator will be the difference in x-coordinates.
As an equation, this is
slope = \frac{y2-y1}{x2-x1},
where the two points are (x1, y1) and (x2, y2).

Let's pick two points to find the slope: (0, 5) and (3, -7).
The slope is 
\frac{-7-5}{3-0} = \frac{-12}{3} = -4

Now that we have the slope m = -4, we need to find the y-intercept b. The line crosses the y-axis at 5, so b = 5.

The equation is y = -4x + 5
6 0
3 years ago
I'm confused on this can you guys please help me. <:
V125BC [204]

Answer:

D. h

Step-by-step explanation:

Since the unknown is height, and height starts with the letter h, h would be most meaningful.

Answer: D. h

8 0
2 years ago
Read 2 more answers
Simplify the expression. HELP, I WANT TO MAKE SURE I DO IT RIGHT
worty [1.4K]
I think the answer to this question is option D
6 0
3 years ago
Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?
oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations  

(x-1)(x+3)=17+x ..... (1) and  

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).  

Therefore, there will be the same solution set for equations (1) and (2).  (Answer)

There are two equations  

(x-1)(x+3)=17+x ..... (3) and  

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).  

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

7 0
3 years ago
Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).
xenn [34]

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

\frac{4}{40} = \frac{40a}{40}

\frac{1}{10} = a

Answer: y = \frac{1}{10}(x - 14)(x + 6)



6 0
3 years ago
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