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Sergio039 [100]
2 years ago
15

Antwan determines the distance between the points –7 and 2 on a number line. Maggie determines the difference between the number

s –7 and 2. How are Antwan’s and Maggie’s solutions related?
Maggie’s solution is the absolute value of Antwan’s solution.

Antwan’s solution is the absolute value of Maggie’s solution.

Both solutions are greater than either of the two numbers in the problem.

Both solutions are less than either of the two numbers in the problem.
Mathematics
1 answer:
-Dominant- [34]2 years ago
6 0

Antawan's solution is the absolute value of Maggie's solution is the solution related to Antawan's and Maggie's solution.

Given

Antawan determines the distance between two points as 9.

Maggie finds the difference between two numbers ₋ 7 ₋ 2 = ₋9

Hence we notice that Antawan's solution is the absolute value to the Maggie's solution.

The non-negative value of x, regardless of its sign, is the absolute value (or modulus) | x | of a real number x. For instance, 5 has an absolute value of 5 and so does 5, which likewise has an absolute value of 5. One way to conceptualize a number's absolute value is as its separation from zero on the real number line.

hence option 2 is right.

Learn more about absolute values here:

brainly.com/question/5012769

#SPJ9

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The answer is , c. 3.4 lol
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√135=3√15.....................

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Jenny is saving money to buy a game. So far she has saved $12, which is one-fourth of the total cost of the game. How much does
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3 years ago
Read 2 more answers
Fill in the blanks to explain how to solve 3/5 divided by 1/10.
MrMuchimi
You can use a common denominator and rewrite 3/5 divided by 1/10 as 6/10 divided by 1/10.
Than you can think, “How many ___s are in ___? (Sorry, i don’t know this part)
3/5 divided 1/10 is 6
7 0
3 years ago
Which option lists am expression that is not equivalent to 4^2/3
Vesnalui [34]

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

4 0
3 years ago
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