7*8/10 product lies between what numbers

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

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If Jose divides his cards into 8 equal stacks, how many cards will there be in each stack? Will there be any cards left over?

gavmur [86]

Idk how many start cards there are o this problem cant be solved...

8 0

3 years ago

I need help with my mathematics exam grade 7 end year!PLEASE help me asap!!PLEASE i beg you :)

AnnyKZ [126]

so first off for the ratios

if you were to find them on a graph, you would want to find a slope. The slope is your ratio pretty much

if you were to find them for a table, you would have to see what the question is asking. if it asking like what is the amount of people vs animals per square mile, you would find people on the table and then go down to square mile as opposed to square feet or some other variable. Then you will put what they are asking first and then what they are asking second. here ill show you an example if it is to confusing what i just said. if there are 50 animals per square mile and 150 people per square mile, and the question asked you what is the ratio between people and animals, you would answer 150/50, BUT you have to simplify. 3/1 would be you answer.

next off for the transformation

if there was a triangle at the points 5,3|4,6|5,5| and you wanted to translate it 5 units up and 6 units to the left, all you do is think about this. up and down are changes in the y, left and right are changes in the x axis. left and down are negative changes, up and right are positive changes.

so you would apply that thinking to ALL the points. it would look something like the picture below.

finally, for the shaded area of figures

lets take a abstract figure. say that we shade the upper left hand corner, and it will look something like the picture below. If you want to find the area of the figure, you would have to isolate it. Then you would multiply the width by the length and get 2.

i really hope this helps on your exam. good luck!

8 0

3 years ago

A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq

alukav5142 [94]

Answer:

13, 14

Step-by-step explanation:

The parameters of the numbers are;

A whole number value = 2 × Another number + 6

The sum of the two numbers is less than 50

Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number

Where 'x' represents the second number, we get;

x + 2·x + 6 < 50

Simplifying gives;

3·x + 6 < 50

x < (50 - 6)/3 = 14. $\overline 6$

x < 14. $\overline 6$

Therefore, the numbers for which the inequality holds true are numbers less than 14. $\overline 6$ . From the given option, the numbers are 13, and 14.

3 0

3 years ago

What is the value of X? 1. 24 2. 13.5 3. 144 4. 2.67

stealth61 [152]

Answer:

i think it would be a 24

Step-by-step explanation:

6×3 = 18

8×3 = 24

6 0

3 years ago

Read 2 more answers