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strojnjashka [21]
2 years ago
7

How do you compare absolute value someone help me asap

Mathematics
1 answer:
Brut [27]2 years ago
3 0

You're trying to find how far that number is from 0 and whether its from the left or right. So -9 is 9 to the left of 0. So the AV of -9 is 9.

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I need to solve this using l'hopital's rule and logarithmic diferentiation.
arlik [135]

Yo sup??

For our convenience let h=x+1

therefore

when x tends to -1, h tends to 0

hence we can rewrite it as

\lim_{h \to \ 0 } (cos(h))^{(cot(h^2 )}

This inequality is of the form 1∞

We will now apply the formula

e^(^g^(^x^)^(^f^(^x^)^-^1^)^)

plugging in the values of g(x) and f(x)

e^{lim_{h \to \ 0}{(cot(h)^2(cos(h)-1))}

express coth² as cosh²/sinh² and also write cosh-1 as 2sin²(h/2)

(by applying the property that cos2x=1-sin²x)

After this multiply the numerator and denominator with h² so that we can apply the property that

\lim_{x \to \ 0 } sinx/x =1

Now your equation will look like this.

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2)*h^2)/(sin(h)^2*h^2)}

We will now apply the result

\lim_{x \to \ 0 } sinx/x =1

where x=h²

we get

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2)}

we now multiply the numerator and denominator with 4 so that we can say

\lim_{h^2 \to \ 0 } sin^2(h/2)/(h^2/4) = 1

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2*4/4)}

=e^{lim_{h \to \ 0}{((cos(h)^2*2)/(4)}

Apply the limits and you will get

e^{cos(0)^2*2/4

=e^{1/2}

Hope this helps.

7 0
3 years ago
Choose two transformations that could have been performed on triangle JKL to form congruent triangle J"K"L".
Svetllana [295]
Triangle JKL was rotated 90° counterclockwise and then refrected across the line y = -4.
3 0
3 years ago
Kaylee is working two summer jobs, making $6 per hour walking dogs and $13 per hours landscaping. Last week Kaylee worked a tota
Aneli [31]

6:13 =83

6+13=19

1 part=83÷19

=4.37

6×4.4=26.4

13×4.4=57.2

26.4:57.2

p.s I got how much money only...

sorry

5 0
4 years ago
What does a variable allow you to do that you couldn't do before
kozerog [31]
For example x^2=25
Without x the expression wouldn't exist, it allows you to calculate unknowns for example in a physics experiment using v=u+at
8 0
3 years ago
2. What is the slope of the line 2x + y = 8?
yawa3891 [41]

Answer:

Using the slope-intercept form, the slope is 2 .

8 0
3 years ago
Read 2 more answers
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