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3 years ago

What is 30% of 40, work it out

Mathematics

1 answer:

aleksley [76]3 years ago

3 0

Answer:

your answer is 12.

30%×40 Is how you work it out.

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Factor the expression using the GCF. A. 2(4a + 8c) B. 4(2a + 4c) C. 8(a + 2c) D. 16( 12 a + c) Not multiple choice

dimulka [17.4K]

Note: The expression is missing. Consider the expression is $8a+16c$ .

Given:

The expression is

$8a+16c$

To find:

Factor form of the given expression by using GCF.

Solution:

We have,

$8a+16c$

Factors of each term:

$8a=2\times 2\times 2\times a$

$16c=2\times 2\times 2\times 2\times c$

The common factors are 2, 2 and 2. So,

$GCF(8a+16c)=2\times 2\times 2$

$GCF(8a+16c)=8$

Taking out the greater common factor (GCF) in the given expression, we get

$8a+16c=8(a+2c)$

Therefore, the required expression is $8(a+2c)$ and the correct option is C.

5 0

3 years ago

Travis runs an average of 25 miles per week give or take six miles. let m be the number of miles travis runs each week

Alinara [238K]

The number of miles Travis runs each week is I m - 25 I = 6<span>.

Let </span><span> m be the number of miles Travis runs each week. Below is the solution:

</span><span>I m - 25 I = 6

19 </span>⇔ 25 ⇔ 31

3 0

3 years ago

Integration questions .

dlinn [17]

$\\\\\ \textbf{a)}\\\\~~~\displaystyle \int (6x- \sin 3x) ~ dx\\\\=6\displaystyle \int x ~ dx - \displaystyle \int \sin 3x ~ dx\\\\=6 \cdot \dfrac{x^2}2 - \dfrac 13 (- \cos 3x) +C~~~~~~~~~~~;\left[\displaystyle \int x^n~ dx = \dfrac{x^{n+1}}{n+1}+C,~~~n \neq -1\right]\\\\ =3x^2 +\dfrac{\cos 3x}3 +C~~~~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \sin (mx) ~dx = -\dfrac 1m ~ (\cos mx)+C \right]\\$

$\textbf{b)}\\\\~~~~\displaystyle \int(3e^{-2x} +\cos (0.5 x)) dx\\\\=3\displaystyle \int e^{-2x} ~dx+ \displaystyle \int \cos(0.5 x) ~dx\\\\\\=-\dfrac 32 e^{-2x} + \dfrac 1{0.5} \sin (0.5 x) +C~~~~~~~~~~~~~~;\left[\displaystyle \int e^{mx}~dx = \dfrac 1m e^{mx} +C \right]\\\\\\=-\dfrac 32 e^{-2x} + 2 \sin(0.5 x) +C~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \cos(mx)~ dx = \dfrac 1m \sin(mx) +C\right]\\\\\\=-1.5e^{-2x} +2\sin(0.5x) +C$

$\textbf{a)}\\\\y = \displaystyle \int \cos(x+5) ~ dx\\\\\text{Let,}\\\\~~~~~~~u = x+5\\\\\implies \dfrac{du}{dx} = 1+0~~~~~~;[\text{Differentiate both sides.}]\\\\\implies \dfrac{du}{dx} = 1\\\\\implies du = dx\\\\\text{Now,}\\\\y= \displaystyle \int \cos u ~ du\\\\~~~= \sin u +C\\\\~~~=\sin(x+5) + C$

$\textbf{b)}\\\\y = \displaystyle \int 2(5x-3)^4 dx\\\\\text{Let,}\\~~~~~~~~u = 5x-3\\\\\implies \dfrac{du}{dx} = 5~~~~~~~~~~;[\text{Differentiate both sides}]\\\\\implies dx = \dfrac{du}5\\\\\text{Now,}\\\\y = 2\cdot \dfrac 1 5 \displaystyle \int u^4 ~ du\\\\\\~~=\dfrac 25 \cdot \dfrac{u^{4+1}}{4+1} +C\\\\\\~~=\dfrac 25 \cdot \dfrac{u^5}5+C\\\\\\~~=\dfrac{2u^5}{25}+C\\\\\\~~=\dfrac{2(5x-3)^5}{25}+C$

$\textbf{a)}\\\\y = \displaystyle \int xe^{3x} dx\\\\\text{We know that,}\\\\ \displaystyle \int (uv) ~dx = u \displaystyle \int v ~ dx - \displaystyle \int \left[ \dfrac{du}{dx} \displaystyle \int ~ v ~ dx \right]~ dx\\\\\text{Let}, u =x~ \text{and}~ v=e^{3x} .\\\\y= \displaystyle \int xe^{3x} ~dx\\\\\\~~= x\displaystyle \int e^{3x} ~ dx - \displaystyle \int \left[\dfrac{d}{dx}(x) \displaystyle \int e^{3x}~ dx \right]~ dx\\\\\\$

$=x\displaystyle \int e^{3x}~ dx - \displaystyle \dfrac 13 \int \left(e^{3x} \right)~ dx\\\\\\=\dfrac{xe^{3x}}3 - \dfrac 13 \cdot \dfrac{ e^{3x}}3+C\\\\\\= \dfrac{xe^{3x}}{3}- \dfrac{e^{3x}}{9}+C\\\\\\=\dfrac{3xe^{3x}}{9}- \dfrac{e^{3x}}9 + C\\\\\\= \dfrac 19e^{3x}(3x-1)+C$

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8 0

2 years ago

Protest question please help ASAP

Anna71 [15]

To find the correct order of similarity we see and compare the sides of both the trapeziums

LM corresponds to QR

KL to PQ

NM to SR

So the correct order should be

KLMN-PQRS

So first Option is correct

8 0

3 years ago

Someone please help me

svlad2 [7]

Y=45x should be the correct answer.

7 0

3 years ago

What is 30% of 40, work it out​

What is 30% of 40, work it out