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gavmur [86]
4 years ago
11

Solve 5/4=y-1/4 Please Help!!!

Mathematics
2 answers:
Contact [7]4 years ago
7 0

Hey there!

Answer = \frac{3}{2}(y= \frac{3}{2})

Explanation:

Let's solve your equation step-by-step.

5/4 = y - 1/4

Simplify both sides of the equation:

\frac{5}{4} =y+\frac{-1}{4}

Flip the equation:

y+\frac{-1}{4}= \frac{5}{4}

Add 1/4 to both sides:

y+\frac{-1}{4} +\frac{1}{4} =\frac{5}{4}+ \frac{1}{4}

y=\frac{3}{2}

So therefore, that is how you found your answer: y=\frac{3}{2}

melomori [17]4 years ago
3 0

Hello!

<u><em>Answer: y=3/2 *The answer must be have a fraction on it.*</em></u>

<u><em>Explanation: First, you had to switch sides of an equation. This gives us, y-1/4=5/4. Then, you add by 1/4 from both sides of an equation. This gives us, y-1/4+1/4=5/4+1/4. And then simplify by equation form. This gives us the final answer is y=3/2 is the correct answer. </em></u>

<u><em>Hope this helps!</em></u>

<u><em>Thanks!</em></u>

<u><em>Have a great day!</em></u>

<u><em>-Charlie</em></u>

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Calculate the percent decrease 34,000 2,720
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7 0
3 years ago
A trumpet has a length of 140cm. The first valve lowers the root note by two semitones (f1/f0 = 2-2/12) and the second valve low
Alexxandr [17]

Answer:

a.  17.145cm

b. 8.325cm

c. 0.846

d. 2.896

Step-by-step explanation:

It is known that frequency is inversely proportional to length.

Case 1: The player presses only the first valve.

f₁/fo = 2^{-2/12} = lo/l₁

given that lo= 140cm.

l₁ = 2^{2/12}lo = 157.145

change in length:

l₁ - lo = 157.145 - 140 = 17.145cm

Case 2: The player presses only the second valve.

f₂/fo = 2^{-1/12} = lo/l₂

l₂ = 2^{1/12}lo = 148.325cm

l₂  - lo= 148.325-140 = 8.325cm

Case 3: The player presses both the first and second valve.

Change in length is the sum of change in length when they are individually pressed.

l₃ - lo = 17.145+8.325 = 25.47cm

l₃ = 25.47cm+lo = 165.47cm

f₃/fo  = 2^{-n/12} = lo/l₃

f₃/fo = 2^{-n/12} = 140/{165.47 = 0.846

2^{-n/12} = 0.846\Rightarrow n/12 = -log(0.846)/log(2) = 0.2413

n = 0.2413*12 = 2.896

5 0
3 years ago
The parallelogram whose diagonals are equal in length and not perpendicular is
mamaluj [8]

Answer:

Rectangle.

Step-by-step explanation:

If the diagonals are equal then the parallelogram is a rectangle. They are also equal in length in a square, which can be regarded as a special type of rectangle - but in this case the diagonals are perpendicular. They are also perpendicular in a rhombus.

4 0
3 years ago
Need explanation 20 points<br> The function f is such that f(x) = 2x - 6<br> Find f^-1(x)
Dvinal [7]

HEYA! <3

Explanation :

<u>GIVEN </u> :

  • f(x) = 2x - 6

<u>TO </u><u>FIND</u><u> </u> :

  • Inverse of f(x) i.e f ^{ - 1} (x)

<u>S</u><u>OLUTION </u> :

FOLLOW THESE THREE STEPS :

  • LET Y = f(x)

\longrightarrow \tt{y = 2x - 6}

\longrightarrow{ \tt{ \: 2x - 6 = y}}

  • MAKE X A SINGLE TERM IN LHS SIDE

\longrightarrow{ \tt{2x = y + 6}}

\longrightarrow{ \tt{x =  \frac{y + 6}{2} }}

  • INTERCHANGE THE VALUE OF X AND Y

\longrightarrow{ \tt{y =  \frac{x + 6}{2} }}

Hence ,

\boxed{ \boxed{ {f}^{ - 1} (x) =   \sf{ \bold{ \frac{x + 6}{2} }}}}

Hope I helped!

Have a wonderful day / night !

  • Feel free to leave comments if you have any queries! :D

4 0
3 years ago
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