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Andrew [12]
3 years ago
6

What is the equation of the line in slope-intercept form that is perpendicular to the line y =

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

it's A on edu

Step-by-step explanation:

took the test

Mice21 [21]3 years ago
4 0
The equation is Y=-4/3x-6
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5/11. the percentage will be:

5/11×100 =500/11

Answer; 45.6

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Evaluate: (x^2-1)/(x-1) if x goes to 1?
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Step-by-step explanation:

\displaystyle \lim_{x \to 1} \dfrac{(x^2 - 1)}{(x-1)} = \lim_{x \to 1} \dfrac{(x - 1)(x+1)}{(x-1)}

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How do you add vectors? Add the vector <3,4> to the vector that goes 7 units at an angle of 2π/3.
lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle \frac{2\pi }{3}

- That means its magnitude is 7 and its direction is  \frac{2\pi }{3}

∴ x = 7 cos(  \frac{2\pi }{3} )

∴ y = 7 sin(  \frac{2\pi }{3} )

∵ cos(  \frac{2\pi }{3} ) =  -\frac{1}{2}

∵ sin(  \frac{2\pi }{3} ) =  \frac{\sqrt{3}}{2}

- Substitute them in x and y

∴ x = (7)( -\frac{1}{2} )

∴ x = -3.5

∴ y = (7)( \frac{\sqrt{3}}{2} )

∴ y = 3.5\sqrt{3}

∴ The vector is <-3.5 , 3.5\sqrt{3}>

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5\sqrt{3} > = <3 + -3.5 , 4 + 3.5\sqrt{3} >

∴  <3 , 4> + <-3.5 , 3.5\sqrt{3}> = <-0.5 , 4+3.5\sqrt{3} >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

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How do you write 12.375 in expanded form
viva [34]
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