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4 years ago

14

Rectangle EFGH is graphed on a coordinate plane with vertices at E(-3,5), F(6,2), G(4,-4),and H (-5,-1). Find the slopes of each

side. What do you notice about the slopes of opposite sides? What do you notice about the slopes of adjacent sides?

1 answer:

meriva4 years ago

5 0

It is a rectangle. 2 sides are even, and 2 others are even.

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In isosceles AEFG shown to the right, EG=EF=10=and GF=12 12. If an altitude was drawn from point E to overline GF what would be

Dovator [93]

You will need to use GCF 12 equals 11 altitude

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3 years ago

Help me quick please?!

docker41 [41]

It is 12/b: opposite/adjacent

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4 years ago

Read 2 more answers

Simplify 2/7 ? I neeed help will give Brainlyest

Fudgin [204]

Answer:

2/7 is already in the simplest form. It can be written as 0.285714 in decimal form (rounded to 6 decimal places).

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3 years ago

What’s the answer to this question if your right I’ll keep giving you points

andreyandreev [35.5K]

$\huge\text{$m\angle O=\boxed{11^{\circ}}$}$

Since we know that all angles in a triangle add up to $180^{\circ}$ , we can solve for $x$ and substitute it back into $(x-5)^{\circ}$ to find $m\angle O$ .

$\begin{aligned}m\angle N+m\angle O+m\angle P&=180\\(5x-8)+(x-5)+(6x+1)&=180\end{aligned}$

Remove the parentheses and combine like terms.

$\begin{aligned}5x-8+x-5+6x+1&=180\\(5x+x+6x)+(-8-5+1)&=180\\12x-12&=180\end{aligned}$

Add $12$ to both sides of the equation.

$\begin{aligned}12x-12&=180\\12x&=192\end{aligned}$

Divide both sides of the equation by $12$ .

$\begin{aligned}x=16\end{aligned}$

Now that we have the value of $x$ , we can substitute it back into $(x-5)^{\circ}$ to find $m\angle O$ .

$\begin{aligned}m\angle O&=(x-5)\\&=16-5\\&=\boxed{11}\end{aligned}$

7 0

3 years ago

3. Find x and m_1<br> 3x +8<br> 6x - 22

Sergio039 [100]

Answer:

The answer to your question is: x = 10; 1 = 142°

Step-by-step explanation:

Find x and m∡ 1

We know that 6x - 22 = 3x + 8 Because they are vertical angles

6x - 3x = 22 + 8 Solve for x

3x = 30

x = 10

Then ∡ = 6(10) - 22

= 60 - 22

= 38°

1 = [360 - 2(38) ] / 2

= [360 - 76] / 2

= 284/2

= 142°

3 0

3 years ago