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2 years ago

A 4kg block moving right at 6 m/s collides elastically with a 2kg block moving right at 3 m/s find their final velocity

Physics

1 answer:

nignag [31]2 years ago

6 0

The final velocity of block 1 is 2.2m/s and the final velocity of block 2 is 3.4m/s.

<h3>What do you mean by elastically?</h3>

Although the terms scalability and elasticity are occasionally used interchangeably, scalability is more commonly used to describe a system's ability to successfully handle an increasing workload, while elasticity implies that the system is also capable of rapidly expanding or decreasing capacity and services. The capacity of an IT environment to grow and shrink in response to business requirements is one of its characteristics. Physics defines resilience as a material's ability to absorb energy and react elastically in order to maintain its integrity and avoid deforming as a result of the pressures it is subjected to.

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Although he did not present a mechanism, what were the key points of Alfred Wegener’s proposal for the concept of continental dr

valentinak56 [21]

Answer: Alfred Wegener provided some of the important points that supported the theory of continental drift. They are as follows-

The continents were once all attached together, and this can be proved by studying the coastlines of some of the continents that perfectly matches with one another.
The appearance of similar rock types and similar fossils (including both animals and plants) has also contributed much information that continents were once all together.

4 0

4 years ago

when a circular plate of metal is heated in an oven, its radius increases at .03 cm/min, at what rate is the area increasing whe

Alinara [238K]

Answer:

Rate of change of area will be $9.796cm^2/min$

Explanation:

We have given rate of change of radius $\frac{dr}{dt}=0.03cm/min$

Radius of the circular plate r = 52 cm

Area is given by $A=\pi r^2$

So $\frac{dA}{dt}=2\pi r\frac{dr}{dt}$

Puting the value of r and $\frac{dr}{dt}$

$\frac{dA}{dt}=2\times 3.14\times 52\times 0.03=9.796cm^2/min$

So rate of change of area will be $9.796cm^2/min$

6 0

3 years ago

What are some ways houses along the coastlines can protect themselves from storm surges?

BARSIC [14]

Build walls around the coast

8 0

3 years ago

A truck with a heavy load has a total mass of 7100 kg. It is climbing a 15∘ incline at a steady 15 m/s when, unfortunately, the

Andrej [43]

Answer:

The load has a mass of 2636.8 kg

Explanation:

Step 1 : Data given

Mass of the truck = 7100 kg

Angle = 15°

velocity = 15m/s

Acceleration = 1.5 m/s²

Mass of truck = m1 kg

Mass of load = m2 kg

Thrust from engine = T

Step 2:

⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:

T = (m1+m2)*g*sinθ

⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes m1*gsinθ .

Resultant force on truck is F = T – m1*gsinθ

F causes the acceleration of the truck: F= m*a

This gives the equation:

T – m1*gsinθ = m1*a

T = m1(a + gsinθ)

Combining both equations gives:

(m1+m2)*g*sinθ = m1*(a + gsinθ)

m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ

m2*g*sinθ = m1*a

Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:

m2*g*sinθ = (7100 – m2)*a

m2*g*sinθ = 7100a – m2a

m2*gsinθ + m2*a = 7100a

m2* (gsinθ + a) = 7100a

m2 = 7100a/(gsinθ + a)

m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)

m2 = 2636.8 kg

The load has a mass of 2636.8 kg

6 0

3 years ago

A car traveling 90.0 km/h is 1500 m behind a truck traveling at 76.0 km/h. 1) How long will it take the car to catch up with the

sergejj [24]

It will take about 3-5 hour

8 0

4 years ago