A 4kg block moving right at 6 m/s collides elastically with a 2kg block moving right at 3 m/s find their final velocity
1 answer:
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The angle of the force is
Explanation:
To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:
where
is the net force along the x-axis
m is the mass of the suitcase
is the acceleration along the x-axis
The suitcase is moving at constant speed, so the acceleration is zero:
Therefore the net force must also be zero:
(1)
We have two forces acting along the horizontal direction:
- The component of the push (forward) in the horizontal direction, , with
F = 43 N
= angle of the force with the horizontal
- The force of friction, , backward
So the net force can be written as
(2)
Combining (1) and (2),
And so we can find the angle:
Learn more about Newton's second law:
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