Answer: The bookkeeper makes cash deposits and records journal entries related to cash, while the treasurer prepares the bank reconciliation.
Explanation: The bookkeeper in an organization is the person in charge of records keeping, his basic task is to keep financial records and therefore the bookkeeper has no business handling physical cash in an organization.
The financial secretary on the hand is in charge saving cash income and withdrawal of cash from an organization, this is done with the organization's accountant approval.
Answer:
0°C.
Explanation:
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In this case, given the heating curve of water on the attached document, we can notice that at 0 °C the solid starts melting, which means that the melting point is reached. Melting point is known as a physical change whereby a solid changes to liquid by the addition of heat as it allows the molecules to separate to each other.
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Answer:
C. 6.99 moles
Explanation:
To convert molecules to moles we simply divide the given number of molecules by Avogadro's number, 6.022 x 10²³
Given number of molecules : 4.21 x 10^24
Number of moles : 4.21 x 10^24 / 6.022 x 10²³ = 6.99 moles ( rounded )
The answer is C
Answer:
<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>
Explanation:
This question is about solubility.
Regarding solubility, the solutions may be classified as:
- Unsaturated: the concentration is below the maximum concentration permited at the given temperature.
- Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.
- Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.
Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.
- In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.
- In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g of water.
- Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ
115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O ⇒ x = 57.5 g NaNO₃
- <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>
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