In the reaction MgCI2+ 2KOH —> Mg(OH)2 + 2KCI if 6 moles MgCI2 are added to 6 miles KOH which is the limiting reagent
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Answer:
0.3152 M
Explanation:
The reaction that takes place is:
- 2MnO₄⁻ + 5C₂O₄⁻² + 16H⁺ → 2Mn⁺² + 8H₂O + 10CO₂
First we <u>calculate the MnO₄⁻ moles used up in the titration</u>, <em>by multiplying the volume times the concentration</em>:
- 21.93 mL * 0.1725 M = 3.783 mmol MnO₄⁻
Then we <u>convert MnO₄⁻ moles to C₂O₄⁻² moles</u>:
- 3.783 mmoles MnO₄⁻ *
= 9.457 mmol C₂O₄⁻²
Finally we <u>calculate the oxalate ion concentration</u>,<em> by dividing the moles by the volume</em>:
- 9.457 mmol C₂O₄⁻² / 30.00 mL = 0.3152 M
Complete Question:
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Answer:
Concepts and reason
This problem is based on the concept of Nuclear magnetic resonance which involves the absorption of radiations in the radio frequency region. This spectroscopy is generally used for the determination of the type and number of protons present in a molecule.
Fundamentals
A spinning charge creates a magnetic field and therefore behaves as a tiny magnet . The spinning nuclei generate a magnetic field on exposure to an external magnetic field . If an external magnetic field is applied , spinning nuclei can get oriented in two ways:
The magnetic field due to nuclei is in the same direction as the external field. In this case, the nuclei are said to be in a low energy spin state.
The magnetic field due to nuclei is in the opposite direction as the external magnetic field. In this case, the nuclei are said to be in high -energy spin state.
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