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1 year ago

Question 2 of 10

Mathematics

1 answer:

andrew-mc [135]1 year ago

6 0

Answer:

B. 15.

Step-by-step explanation:

In order to get this answer, we just need to substitute the value of x in the formula and calculate the answer. Let's rewrite the expression with the substituions:

4((5)+5) ((5)+1) / ((5)+3) ((5)-3) = (40) (6) / (8) (2)= 240/16= 15.

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2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long

Makovka662 [10]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that $r = 0.07, P(0) = 1.79$ . So

$P(t) = P(0)(1+r)^{t}$

$P(t) = 1.79(1+0.07)^{t}$

$P(t) = 1.79(1.07)^{t}$

What did it cost 10 years ago?

$P(-10) = 1.79(1.07)^{-10} = 0.91$

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

$P(t) = 1.79(1.07)^{t}$

$2*1.79 = 1.79(1.07)^{t}$

$(1.07)^{t} = 2$

$\log{(1.07)^{t}} = \log{2}$

$t\log{1.07} = \log{2}$

$t = \frac{\log{2}}{\log{1.07}}$

$t = 10.24$

It takes 10.24 years for the cost of bread to double.

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