Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
2(-3n-5)-5(4n-8)
(-6n-10)+(-20n+40)
-26n-30
Answer:
exact form is 56/37
decimal form is 1.513
mixed number form is 1 19/37
Step-by-step explanation:
Answer:
JL = 78
Step-by-step explanation:
MN is a midsegment. Based on the midsegment theorem,
MN = ½(JL)
MN = 5x - 16
JL = 4x + 34
Plug in the value
5x - 16 = ½(4x + 34)
5x - 16 = ½*4x + ½*34
5x - 16 = 2x + 17
Collect like terms
5x - 2x = 16 + 17
3x = 33
Divide both sides by 3
x = 11
✔️JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34
JL = 44 + 34
JL = 78
<span>The simple interest formula is:
A = P · (1 + r · t)
where:
A = total amount
P = principal
r = rate
t = time
Let's solve for r:
A = P + P · r · t
P · r · t = A - P
r = (A - P) / (P · t)
The quantity A - P is defined as the Interest, therefore:
r = I / (P <span>· t)
= 1020 / (8500 </span>· 4)
= 0.03
Therefore the rate was 3%.
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