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Vlad [161]
1 year ago
12

What is the greatest possible quotient of any two distinct members of the set $\left\{\frac{2}{5}, \frac{1}{2},5,10\right\}$

Mathematics
1 answer:
MA_775_DIABLO [31]1 year ago
8 0

The greatest possible quotient of two distinct members of the set is 25.

<h3>What is the Quotient?</h3>

A quotient is defined as the outcome of dividing an integer by any divisor that can be said to be a quotient. The dividend contains the divisor a specific number of times.

We are given the set of numbers as :

2/5, 1/2, 5, 10

We must choose p as the biggest number from the set and q as the smallest number from the set in order to the greatest possible quotient .

Comparing the fractions we determine :

⇒ 2/5 = 0.4,

⇒ 1/2 = 0.5

So, the smallest number is 2/5

Select p = 10, q = 2/5

To determine the quotient.

So, p/q = 10/(2/5)

⇒ p/q = 10×5/2

⇒ p/q = 50/2

⇒ p/q = 25

Hence, the greatest possible quotient is 25 in the set.

Learn more about the quotient here:

brainly.com/question/27796160

#SPJ1

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C

Step-by-step explanation:

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Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Can someone please help me
Readme [11.4K]
Surface Area of the figure is 1208 square centimeters
a=20
b=13
c=12
d=5
e=8
Top face:
A1=a×e=20×8
ae=160
Bottom face:
A2(a+2d)×e=(20+2×5)×8=(20+10)×8=30×8
(a+2d)e=240
Front face:
Rectangle
a×c=20×12=240
Triangle:
12c×d=12×12×5=6×5=30
A3Rectangle +2 triangles
240+2×30=240+60=300
(a+d)c=300
Slant face:
A4=b×e=13×8=104
be=104
Total surface area
A=A1+A2+2(A3+A4)
A1=160
A2=240
A3=300
A4=104
Thus,
A=160+240+2(300+104)
A=400+2(404)
A=400+808=1208
Surface Area of the figure is 1208 square centimeters


8 0
3 years ago
A) 7xy?<br> Degree and number of terms
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Answer:

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Step-by-step explanation:

degree of 1 and 1 term.

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3 years ago
HELP PLZZZZZ OMGGGGGGG
Sidana [21]
The money is a lot so it would be c
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