Answer:
θ = 2 π n_1 + π/2 for n_1 element Z or θ = 2 π n_2 for n_2 element Z
Step-by-step explanation:
Solve for θ:
cos(θ) + sin(θ) = 1
cos(θ) + sin(θ) = sqrt(2) (cos(θ)/sqrt(2) + sin(θ)/sqrt(2)) = sqrt(2) (sin(π/4) cos(θ) + cos(π/4) sin(θ)) = sqrt(2) sin(θ + π/4):
sqrt(2) sin(θ + π/4) = 1
Divide both sides by sqrt(2):
sin(θ + π/4) = 1/sqrt(2)
Take the inverse sine of both sides:
θ + π/4 = 2 π n_1 + (3 π)/4 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
θ = 2 π n_1 + π/2 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
Answer: θ = 2 π n_1 + π/2 for n_1 element Z
or θ = 2 π n_2 for n_2 element Z
The answer is exponential decay
there's no exact answer for it because pi goes on forever
No it does not affect the sum because they have the same sign so it wouldn't make a difference
