I have a 82.92 in anatomy class but I recieved a 60 percent on an exam.. what will this bring my grade to?

Solve the System of Equations

soldi70 [24.7K]

Answer:

Equations: $x+y=80\,,\,2x+4y=216\,\,$

number of chickens = 52

number of goats = 28

Step-by-step explanation:

Given: A small ranch has chickens and goats

Total number of heads = 80

Total number of legs = 216

To find: number of chickens and goats

To draw: the graph

Solution:

Let x denotes number of chickens and y denotes number of goats.

According to the question,

$x+y=80\,\,(i)\\2x+4y=216\,\,(ii)$

From (i), put $x=80-y$ in (ii)

$2(80-y)+4y=216\\160-2y+4y=216\\2y=216-180\\2y=56\\y=\frac{56}{2}=28$

Put $y=28$ in equation (i)

$x+28=80\\x=80-28=52$

So,

number of chickens = 52

number of goats = 28

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6 0

3 years ago

How would I calculate the horizontal distance of a parabola?

maks197457 [2]

X = y2 is the equation for it just plug in the numbers

7 0

2 years ago

Mr. Fox purchased 76 bags of candy to make treat bags each bag contains 48 pieces of candy how many pieces of candy did Mr. Fox

cluponka [151]

3,648 (three thousand six hundred fourty eight) pieces of candy!

4 0

3 years ago

Read 2 more answers

Axis of sym: x =

marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic function
PEMDAS

<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

y=a(x-h)²+k

therefore

y=a(x-(-1))²+4
y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

$3 = a(1 {)}^{2} + 4$

simplify exponent:

$3 = a + 4$

therefore

$a = - 1$

our vertex form of quadratic equation is

y=-(x+1)²+4

let's simplify it to standard form

simplify square:

$y = - ( {x}^{2} + 2x + 1) + 4$

simplify parentheses:

$y = - {x}^{2} - 2x - 1 + 4$

simplify addition:

$y = - {x}^{2} - 2x + 3$

therefore our answer is D)y=-x²-2x+3

the domain of the function

$x\in \mathbb{R}$

and the range of the function is

$y\leqslant 4$

zeroes of the function:

$- {x}^{2} - 2x + 3 = 0$

$\sf divide \: both \: sides \: by \: - 1$

${x}^{2} + 2x - 3 = 0$

$\implies \: {x}^{2} + 3x - x + 3 = 0$

factor out x and -1 respectively:

$\sf \implies \: x(x + 3) - 1(x + 3 )= 0$

group:

$\implies \: (x - 1)(x + 3) = 0$

therefore

$\begin{cases} x_{1} = 1 \\ x_{2} = - 3\end{cases}$

4 0

3 years ago

Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through th

Dominik [7]

y = 0.6x - 3.2
The general form of the desired equation is
y = mx + b
where
m = slope of the line
b = y intercept of the line
If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
y = 0.6x + b
Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
y = 0.6x + b
-5 = 0.6(-3) + b
-5 = -1.8 + b
-3.2 = b
So the desired equation is now
y = 0.6x - 3.2

3 0

3 years ago