Question

A triangle having perimeter 56 cm and its sides are 2b, 2b +3 and 2b +5. Find the lengths of the sides of the triangle.​

Answer 1

Answer:

16, 19 & 21 cm

Step-by-step explanation:

add the sides and form the equation

2b + (2b + 3) + (2b + 5) = 56

6b + 8 = 56

6b = 56 - 8

6b = 48

b = 48 / 6 = 8

calculate the sides:

Side one: 2b = 2(8) = 16 cm

Side two: 2b + 3 = 2(8) + 3 = 16 + 3 = 19 cm

Side three: 2b + 5 = 2(8) + 5 = 16 + 5 = 21 cm

perimeter = 16 + 19 + 21 = 56 cm

Hope this helps