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sp2606 [1]
1 year ago
15

Can someone pls help me with this !

Mathematics
1 answer:
Vadim26 [7]1 year ago
8 0

Using a line of best fit, the predicted tsunami speed for the following depths is given by:

a. 1151 km/h.

b. 572 km/h.

c. 130 km/h.

d. 122 km/h.

<h3>How to find the equation of linear regression using a calculator?</h3>

To find the equation, we need to insert the points (x,y) in the calculator.

For this problem, the points (depth, velocity) are given by:

(7000, 943), (4000, 713), (2000, 504), (200, 159), (50, 79), (10,36)

Inserting these points in the calculator, the velocity in function of the depth is:

v(d) = 0.12879d + 121.03448

Hence, the velocities are given as follows:

a. v(8000) = 0.12879 x 8000 + 121.03448 = 1151 km/h.

b. v(3500) = 0.12879 x 3500 + 121.03448 = 572 km/h.

c. v(70) = 0.12879 x 70 + 121.03448 = 130 km/h.

d. v(5) = 0.12879 x 5 + 121.03448 = 122 km/h.

More can be learned about a line of best fit at brainly.com/question/13203683

#SPJ1

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If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
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\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


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