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koban [17]
3 years ago
5

On a particular day, the wind added 4 miles per hour to Alfonso’s rate when he was cycling with the wind and subtracted 4 miles

per hour from his rate on his return trip. Alfonso found that in the same amount of time he could cycle 68 miles with the wind, he could go only 30 miles against the wind. What is his normal bicycling speed with no wind?
Mathematics
1 answer:
Greeley [361]3 years ago
8 0

d = r · t ⇒ t = d/r

going

t = 54/(r + 4)

coming

t = 30/(r - 4)

54/(r + 4) = 30/(r - 4) times are equal

54(r - 4) = 30(r + 4) product means/extremes

54r - 216 = 30r + 120 distribute

24r - 216 = 120 subtract 30r from both sides

24r = 336 add 216 to both sides

r = 14 divide both sides by 24

Alfonso bikes at 24 mph.

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If a dolphin eat 30 pounds of fish per day how much will it eat in 30 days
alexgriva [62]

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3 years ago
Which of the following equations is equivalent to S=pi r^2 h
lara31 [8.8K]

The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

We are to make 'h" the subject of the formula.

Divide both sides by pir^2

S/pir^2 =pi r^2 h/pir^2

h = S/pir^2

Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2

Learn more on subject of formula here: brainly.com/question/657646

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4 0
2 years ago
A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of
krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

QR=chord =radius =R

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus QO=\frac{R}{2}=RO

In triangle PQO applying Pythagoras theorem

(PQ)^2=(PO)^2+(QO)^2

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PO=\sqrt{R^2-\frac{R^2}{4}}

PO=\frac{\sqrt{3}}{2}R

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5 0
3 years ago
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