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lisov135 [29]
1 year ago
13

If your current examination mean is 97.2 and you receive a 99 on the next examination, what effect will this have?

Mathematics
2 answers:
Sonbull [250]1 year ago
6 0

If your current examination mean is 97.2 and you receive a 99 on the next examination, the mean will increases.

Mean: It is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the number of values on the list. To find the mean, add up all the values in the set. Then divide the sum by how many values there are.

We have the current examination mean, x_o_l_d = 97.2

Now, we receive, x = 99 on the next examination, the new mean will be:

x_n_e_w = \frac{x_o_l_d + x}{N}                                                                ∴ N= 2

x_n_e_w = \frac{97.2 + 99}{2}

x_n_e_w = \frac{196.2}{2}

x_n_e_w = 98.1

∴ New mean, x_n_e_w = 98.1

98.1 > 97.2

Hence, mean is increased on receiving a 99 on the next examination.

For more information on this topic, visit:

brainly.com/question/1136789

#SPJ4

mr Goodwill [35]1 year ago
3 0

If you have an average of 97.2 on your current exam and you get a 99 on your next exam, your average will increase.

  • Mean in mathematics is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the total number of values.

  • To find the average, sum all the values ​​in the set. Then divide the total by the number of values.

We have the current examination mean, xold = 97.2

Now, we receive,  x = 99 on the next examination, the new mean will be:

xnew = (xold + x)/N

xnew = (97.2+99)/2

xnew = 196.2/2

xnew = 98.1  

The new average is 98.1

98.1 > 97.2

So if you score 99 on your next exam, your average will increase.

Learn more about mean here

brainly.com/question/1136789

#SPJ4

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Step-by-step explanation:

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Step-by-step explanation:

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By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

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