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Aleonysh [2.5K]
3 years ago
11

How do I write a part to whole ratio as a percent

Mathematics
2 answers:
nirvana33 [79]3 years ago
6 0

Step-by-step explanation:

simplify the ratio

ex: 15:20

3:4

then change the ratio to a fraction

ex: 3:4

3/4

then change a fraction to a percent

ex: 3/4 =75%

Fed [463]3 years ago
5 0
You simplify your ratio as much as you can, then make it a fraction. Once it’s in the form of a fraction, it’s easier to make it into a percent
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Distribute (2m-5m)(-5)
Reika [66]

First Method (Distributive Property)

(2m - 5m) (-5)

Rearrange the equation to make it easier.

(-5) (2m - 5m)

In distributive property, it's all about multiplying. The -5 goes to the 2m and the 5m. Like this: (-5 • 2m) - (-5 • 5m).

-10m + 25m

15m

Second Method

(2m - 5m) (-5)

Since 2m and 5m have the same variable, we can subtract them.

(-3m) (-5)

Multiply.

15m

15m is your answer. I hope this helps!

6 0
3 years ago
One of the factors of 34 is chosen at random. What is the probability that the factor is itself a two digit number?
solong [7]
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?

The positive whole-number factors of 30 are:

1, 2, 3, 5, 6, 10, 15 and 30.

So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that

P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors

=38=3×.125=.375
8 0
2 years ago
X/3-4=-7<br><br> please help me solve
Vanyuwa [196]
In order to solve this we need to get x by itself on one side.

We need o start by adding across the 4 so that we get:

x/3 = -7 + 4 = -3

We then need to multiply both sides by 3 to get a singular x:

x = -3 * 3 = -9
5 0
3 years ago
Read 2 more answers
Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note
Viktor [21]

a. Recall that

\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C

For |x|, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

By integrating both sides, we get

\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

If x=0, then

\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0

so that

\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

We can shift the index to simplify the sum slightly.

\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n

b. The power series for x\ln(1-x) can be obtained simply by multiplying both sides of the series above by x.

\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n

c. We have

\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)

\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}

4 0
3 years ago
When six is subtracted from five times a number, the result is 9
Andreas93 [3]

Answer: Think it is -3/5

Step-by-step explanation:

6-5(x)=9

6-5(-3/5)=9

6+3=9

9=9

4 0
3 years ago
Read 2 more answers
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