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1 year ago

6x-4bracket(2x-5)>8 or 5x+9<2x-21

Mathematics

1 answer:

Yuri [45]1 year ago

4 0

The solutions to the given inequalities are x < 6 OR x < -10

<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21

First solve,

6x - 4(2x - 5) > 8

Clear the bracket

6x -8x + 20 > 8

6x - 8x > 8 - 20

-2x > -12

Divide both sides by -2 and flip the sign,

That is,

-2x/-2 > -12/-2

x < 6

For,

5x + 9 < 2x - 21

Subtract 2x from both sides

5x - 2x + 9 < 2x - 2x -21

3x < -21 -9

3x < -30

Divide both sides by 3

3x/3 < -30/3

x < -10

Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

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Answer these Questions for me pleaseeeee....

Thepotemich [5.8K]

Answer:

A. 31

B. 5

C. 9/31 or 0.29%

D. 2/31 or 0.06%

E. 0 or unknown

Step-by-step explanation:

A is the addition of all the entries, B is the number of entries that said snakes, C and D are about how many out of the total can give you the corresponding animal, chances are always part/total so for C it's 9/31 and D is 2/31. E is 0 or unknown because there is no "Frog" entries as favorite pet so it must be either 0 or unknown because you don't get the information

<em>pls brainliest if you found useful</em>

3 0

3 years ago

1. Find the area of the following geometric figure.

S_A_V [24]

Answer:

1. Area of the triangle is $96m^2$ .

2. 2 gallons of paint will you need to cover 224 sq.ft

3. Volume of the following solid(to the nearest tenth), is 580.1 $cm^3$ .

4. The area cover is 242 sq. ft.

5. The sides of the triangle on the drawing should be 6, 8, and 9 inch

Step-by-step explanation:

<u>Given:</u>

Base of the triangle(b) is 16 m

and altitude of the triangle(h) is 12 m.

To find the Area of the triangle(A), given by;

$A=\frac{1}{2}\left (b\cdot h\right)$

$A=\frac{1}{2}\left (16\cdot 12\right)$ $=8 \cdot 12=96 m^2$

Therefore, the Area of the triangle is $96m^2$ .

Given: You wish to paint a storage shed. Its four walls measure 7 ft. high and 8 ft. wide each.

First find the area(A) of one wall.

$A=b\cdot h$

where b is the width and h is the height of the wall.

$A=8ft\cdot 7ft$ = $56ft^2$ .

Now, area for four walls is, $4\cdot 56=224 ft^2$

Since, one gallon of paint covers 160 sq. ft or we can say that 160 sq. ft cover in one gallon of paint.

for 224 sq ft cover in , $\frac{224}{160} =1.4$ gallon of paint

2 gallons of paint will you need to cover 224 sq.ft.

Given: A rectangular solid has sides of 10.5 cm, 6.5 cm, and 8.5 cm

length (l)=10.5 cm

breadth(b)=6.5 cm

height(h)=8.5 cm

Volume of rectangular solid(V) is given by, $V=lbh$

$v=10.5\cdot 6.5\cdot 8.5$ $=580.125 cm^3$

Therefore, the volume of the following solid(to the nearest tenth), is 580.1 $cm^3$ .

Given: You are laying an asphalt driveway. if the driveway is 22 feet long and 11 feet wide.

length(l)=22 ft

Wide(w)= 11 ft

Area cover (A) is given by, $A=lw$

$A=22\cdot 11=242 ft^2$

Therefore, the area cover is 242 sq. ft.

Given: A triangle with sides 12 feet, 16 feet, and 18 feet on a drawing

Use: 1 inch = 2 feet.

Convert each sides of a triangle into inches.

12 feet

1 inch = 2 feet

12 feet = 6 inch

similarly, others sides 16 feet = 8 inch and 18 feet = 9 inch

Therefore, the sides of the triangle on the drawing should be 6 inch, 8 inch, and 9 inch

3 0

3 years ago

Read 2 more answers

The average radius of Jupiter is 4.34 x 10^4 miles. The average sun radius of the sun is 4.32 x 10^5. How many times greater is

Oksanka [162]

Answer:

The average radius of sun is approximately 9.95 times the average radius of Jupiter.

Step-by-step explanation:

We are given the following in the question:

Average radius of Jupiter =

$4.34\times 10^{4}\text{ miles}$

Average radius of the sun =

$4.32\times 10^{5}$

Relation between average radius of sun and average radius of Jupiter =

$\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}}\\\\= \frac{4.32\times 10^{5}}{4.34\times 10^{4}}\\\\\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}} = 9.953917\\\\\text{Average radius of Sun} \approx 9.95\times \text{(Average radius of Jupiter)}$