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Sever21 [200]
1 year ago
11

6x-4bracket(2x-5)>8 or 5x+9<2x-21

Mathematics
1 answer:
Yuri [45]1 year ago
4 0

The solutions to the given inequalities are x < 6 OR x < -10

<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21

First solve,

6x - 4(2x - 5) > 8

Clear the bracket

6x -8x + 20 > 8

6x - 8x > 8 - 20

-2x > -12

Divide both sides by -2 and flip the sign,

That is,

-2x/-2 > -12/-2

x < 6

For,

5x + 9 < 2x - 21

Subtract 2x from both sides

5x - 2x + 9 < 2x - 2x -21

3x < -21 -9

3x < -30

Divide both sides by 3

3x/3 < -30/3

x < -10

Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

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&lt;1 and &lt;2 are supplementary angles. m &lt;1 is 4y+7, and m&lt;2 is 9y+4. Find m&lt;2.
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Okay, so supplementary angles = 180 degrees.

Starting equation : 4y + 7 + 9y + 4 = 180

Combine like terms : 13y + 11 = 180

Subtract 11 from both sides : 13y = 169

Divide 13 from both sides : y = 13

Insert y value into original m<2 equation : 9(13) + 4

Solve : 121 degrees


If you want to check your work, all you have to do is insert y value into original m<1 equation and then add both m<1 and m<2. If they equal 180, your answer is correct.

4(13) + 7 = 59

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