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Sever21 [200]
1 year ago
11

6x-4bracket(2x-5)>8 or 5x+9<2x-21

Mathematics
1 answer:
Yuri [45]1 year ago
4 0

The solutions to the given inequalities are x < 6 OR x < -10

<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21

First solve,

6x - 4(2x - 5) > 8

Clear the bracket

6x -8x + 20 > 8

6x - 8x > 8 - 20

-2x > -12

Divide both sides by -2 and flip the sign,

That is,

-2x/-2 > -12/-2

x < 6

For,

5x + 9 < 2x - 21

Subtract 2x from both sides

5x - 2x + 9 < 2x - 2x -21

3x < -21 -9

3x < -30

Divide both sides by 3

3x/3 < -30/3

x < -10

Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

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Answer: -54

Step-by-step explanation:

The question is the first term of a geometric sequence is −2 and the common ratio is 3. The formula for finding the nth term of a geometric sequence is: ar^n-1

where,

a = first term = -2

r = common ratio = 3

n = number of terms = 4

The solution has been attached. The answer is -54

5 0
3 years ago
Verify which of the following are identities.
-Dominant- [34]

Answer:

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Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

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<u>Therefore</u>

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<h2>It is not an Identity</h2>

<u>Let's the second one</u>

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In this case, we already performed the calculations, so it is true. It is an Identity.

3 0
3 years ago
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Answer:

Tyrone

Step-by-step explanation:

In a race the shortest time is the winner.

In this case the ones and  the tens place are all the same so we look to the tenths place in which Tyrone has a 0 which is the lowest.

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Step-by-step explanation:

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