Answer:
No
Step-by-step explanation:
_2 and 2.5 are not a natural number's . the set of rational numbers however is closed to respect to multiplication division and addition and subtraction
Answer:
a) Drag force = 5.67 N
b) Fraction of (drag force/weight) = 0.00964 = 0.964% (just less than 1%)
Step-by-step explanation:
Drag force is given by the expression
Drag force = CρAv²/2
C = Drag coefficient of air for an average human moving through air = 1.0
ρ = density of air = 1.2 kg/m³
A = Cross sectional Area of runner facing the air = 0.72 m²
v = velocity of the runner = (5km/23min) = (5000/23×60) = 3.623 m/s
Drag force = 1(1.2)(0.72)(3.623²)/2
Drag force = 5.67 N
b) Runner's weight = mg = 60×9.8 = 588 N
Fraction of (drag force/weight) = (5.67/588) = 0.00964 = 0.964% (just less than 1%)
Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder= 
Considering, π= 3.14
⇒ lateral surface area of cylinder= 
⇒ lateral surface area of cylinder= 
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution= 
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
Answer:
(-2,4)
Step-by-step explanation:
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