Question

At a pizza shop, 75% of the customers order pizza, 20% of the customers order salad, and 15% of the customers order a pizza and a salad. If a costumer isn’t chosen at random, what is the probability that he or she orders either a pizza or salad?

Answer 1

Answer:

The probability that he or she orders either a pizza or salad is 80%.

Step-by-step explanation:

Given : At a pizza shop, 75% of the customers order pizza, 20% of the customers order salad, and 15% of the customers order a pizza and a salad. If a costumer isn’t chosen at random.

To find : What is the probability that he or she orders either a pizza or salad?

Solution :      

Let A be the event that customer order Pizza

Let B be the event that customer order Salad

75% of the customers order pizza,

P(A)=75%=0.75

20% of the customers order salad,

P(B)=20%=0.20

15% of the customers order a pizza and a salad,

$P(A\cap B)=15%=0.15$

Now, The probability that he or she orders either a pizza or salad

$P(A\cup B)= P(A)+P(B)-P(A\cap B)$

$P(A\cup B)= 0.75+0.20-0.15$

$P(A\cup B)= 0.95-0.15$

$P(A\cup B)= 0.80$

Therefore, The probability that he or she orders either a pizza or salad is 80%.

Answer 2

Better probability of them getting pizza