o is the centre of a circle PQ is a chord and PT is a tangent at P if angle POQ is 70° then find angle TPQ
1 answer:
Answer:
< TPQ = 145 degrees
Step-by-step explanation:
< QPO = (180 - 70)/2 = 55 degrees ( base angle of an isosceles triangle).
< OPT = 90 degrees ( OP is a radius to point of contact of the tangent).
Therefore < TPQ = < QPO + < OPT
= 55 + 90
= 145 degrees
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