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2 years ago

My question is in the picture.

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

8 0

Answer: the have the same rate of change

Step-by-step explanation:

the rate of change for p is 2x and for q because it goes up 2 steps and across it shows that it is 2/1x witch is also 2x

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The higher price of a commodity is ¢565.00

EastWind [94]

Answer:

There is no question to answer. This is simply just a statement. If you need help, feel free to put the question under this comment because I don't understand what anyone is supposed to be answering from this "question."

5 0

3 years ago

Which of the following linear equations represents the data chart?

BlackZzzverrR [31]

Answer: y = -x + 7

Step-by-step explanation:

The slope is $\frac{5-6}{2-1}=-1$ , so we know the equation is of the form $y=-x+b$ .

Substituting in the coordinates (1,6) to find b,

$6=-1+b\\\\b=7$

Thus, the equation is y = -x + 7

4 0

2 years ago

1. Ginger has 31 drinking straws. If each

wolverine [178]

31 x 7.875 = 244.125

244.125 inches altogether

6 0

3 years ago

A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the

charle [14.2K]

Answer:

$\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

Step-by-step explanation:

Volume of water in the tank = 1000 L

Let y(t) denote the amount of salt in the tank at any time t.

Initially, the tank contains 60 kg of salt, therefore:

y(0)=60 kg

Rate In

A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.

$R_{in}$ =(concentration of salt in inflow)(input rate of solution)

$=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}$

Rate Out

The solution is mixed and drains from the tank at the same rate.

Concentration, $C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}$

$R_{out}$ =(concentration of salt in outflow)(output rate of solution)

$=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}$

Therefore, the differential equation for the amount of Salt in the Tank at any time t:

$\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

8 0

4 years ago

a store sold 14.00 dollars worth of gift cards in october. the next month the goal was to sell $15.96 worth of gift points. this

solniwko [45]

Subtract 14 from 15.96 to find the increase.
15.96 - 14 = 1.96
Divide 1.96 by 14.
1.96 / 14 = 0.14
In percents that is 14%.
This is an increase of 14%.
Hope this helps!

4 0

3 years ago

Read 2 more answers