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4 years ago

Is there a rigid transformation taking Rhombus P to Rhombus Q? Explain how you know.

Mathematics

1 answer:

miss Akunina [59]4 years ago

4 0

Answer:

There's no rigid transformation

Step-by-step explanation:

<em>The attachment is blank; See attachment for clear picture of rhombus</em>

Required

State if there's a rigid transformation between P and Q

The term rigid transformation implies that there's no change in any two or more given shapes as long as the size is being considered.

Looking at both rhombus, you observe that rhombus P and Q have different dimensions.

So, we can conclude that there's no rigid transformation from rhombus P to Q .

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mafiozo [28]

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3 years ago

Zev read 15% of his 56-page book. Kelly read 12% of her 64-page book. Marneisha read 14% of his 68-page book Aleisha read 10% of

GrogVix [38]

Answer:

Marneisha with 9.52 pages.

Step-by-step explanation:

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4 years ago

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mezya [45]

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3 years ago

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Gemiola [76]

Answer:

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3 years ago

PLEASEE HELP AGAINNNN!!!!<br> If a1 = 4 and an = -4an - 1 then find the value of a6

sertanlavr [38]

The 6th term of the geometric sequence is of -4096.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term.

For this problem, we have that:

The first term is $a_1 = 4$ .

$a_n = -4a_{n - 1}$ , hence the common ratio is q = -4.

Thus the 6th term of the sequence is found as follows:

$a_6 = a_1q^5 = 4(-4)^5 = -4096$

More can be learned about geometric sequences at brainly.com/question/11847927

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1 year ago