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vovikov84 [41]
3 years ago
12

a store sold 14.00 dollars worth of gift cards in october. the next month the goal was to sell $15.96 worth of gift points. this

is an increase of ___percent
Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
This would be 14% because as decimal it's 0.14 which is 14 hundredths.
solniwko [45]3 years ago
4 0
Subtract 14 from 15.96 to find the increase. 
15.96 - 14 = 1.96 
Divide 1.96 by 14. 
1.96 / 14 = 0.14 
In percents that is 14%. 
This is an increase of 14%. 
Hope this helps!
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Answer:

Goku (Super Saiyan 3)

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7 0
3 years ago
Read 2 more answers
4/f + 11 =29 what does f =
Delvig [45]
\frac{4}{f} + 11 = 29

First, subtract '11' from each side.
\frac{4}{f} = 29 - 11

Second, subtract '29 - 11' to get '18'.
\frac{4}{f} = 18

Third, since we are solving for f, we have to get it by itself. Multiply each side by 'f'.
4 = 18f

Fourth, once again, we need to get 'f' alone. Divide both sides by 18. 
\frac{4}{18} = f

Fifth, now that we have 'f' by itself, we can simplify the current fraction. To do so, we need to start off with listing the factors of 4 and 18 and find the greatest common factor (GCF).

Factors of 4: 1, 2, 4
Factors of 18: 1, 2, 3, 6, 9, 18

Out of the listed factors, 1 and 2 are the common factors, and since 2 is the highest number out of them, it is considered the greatest common factor. The GCF is 2.

Sixth, divide the numerator and denominator by the GCF (2).
4 \div 2 = 2  \\  18 \div 2 = 9

Seventh, we can now rewrite our fraction in simplest form and switch sides.
f =  \frac{2}{9}

Answer in fraction form: \fbox {2/9}
Answer in decimal form: \fbox {0.2222}

7 0
3 years ago
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This H.W I dont get it plz help.
steposvetlana [31]
I think it’s D I’m not sure
4 0
3 years ago
Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4
lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

4p(y-k)=(x-h)^{2}

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

4(4)(y-3)=4(4)(x-2)^{2}

16(y-3)=(x-2)^{2}

(y-3)=(1/16)(x-2)^{2}

8 0
3 years ago
I need help plz its basic trig
Levart [38]

Answer:

i dont know it srry

Step-by-step explanation:

8 0
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