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belka [17]
2 years ago
9

What is the y-intercept of y=[x-41 +1? ○ (0,-5) O (5,5) (0,5) ○ (5,0)

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
8 0

The y-intercept of the given function is (0, -5)

<h3>y-intercept of an equation</h3>

Given the equation below

y=[x-4| +1

The y-intercept is the point where the value of x is zero. Substitute x = 0 into the function to have;

y = 0 - 4-  1

y = 0 - 5

y = -5

Hence the y-intercept of the given function is (0, -5)

Learn more on y-intercept here: brainly.com/question/24363347

#SPJ1

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3 years ago
The price elasticity of demand for good X is half the price elasticity of Good Y. A 20% rise in the price of good X results in a
Keith_Richards [23]

The answer is

60% rise in quantity demanded of good x.

Explanation:

Percentage change in quantity demanded for good Y:

= (Change in Quantity ÷ Initial Quantity) × 100

= (60 units ÷ 400 units) × 100

= 15%

Percentage change in price of good Y = 10% Rise

Therefore, the price elasticity of demand for Good Y is as follows:

= Percentage change in Quantity demanded ÷ Percentage change in price

= 15 ÷ 10

= 1.5

Hence,

Price elasticity of demand of good x:

= 2 × price elasticity of demand of good y

= 2 × 1.5

= 3

Percentage change in price of good x:

= (Change in price ÷ Initial price) × 100

= (2 ÷ 10) × 100

= 20%

Therefore,

Price elasticity of demand for Good x = Percentage change in Quantity demanded ÷ Percentage change in price

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3 × 20 = Percentage change in Quantity demanded

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Hence, 60% rise in quantity demanded of good x.

7 0
3 years ago
Precalculus PLEASE HELP ME right answers only check all please
Alex_Xolod [135]

Given :

cos(x)cos(\frac{\pi }{7}) + sin(x)sin(\frac{\pi }{7})=-\frac{\sqrt{2}}{2}

We know the identity

cos(x)cos(y) + sin(x)sin(y)=cos(x-y)

We use this property to simplify the left hand side

So  cos(x)cos(\frac{\pi }{7}) + sin(x)sin(\frac{\pi }{7})=cos(x - \frac{\pi }{7})

cos(x - \frac{\pi }{7}) =-\frac{\sqrt{2}}{2})

we know ,

when cos(x) =-\frac{\sqrt{2}}{2}) then

x = \frac{3\pi }{4} , \frac{5\pi }{4}

For  cos(x - \frac{\pi }{7}) =-\frac{\sqrt{2}}{2})

x - \frac{\pi }{7}= \frac{3\pi }{4} and x - \frac{\pi }{7}= \frac{5\pi }{4}

Add \frac{\pi }{7} on both sides

x= \frac{3\pi }{4} + \frac{\pi }{7} and x= \frac{5\pi }{4} +\frac{\pi }{7}

Finally we add 2npi for general solution

So options C  and D  are correct


6 0
3 years ago
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