8+4st-16t
you should multiply the terms after and before parentheses in each term of parenthes...
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Addition/Subtraction]:
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Reverse Power Rule]: 
Integration Rule [Fundamental Theorem of Calculus 1]: 
Integration Property [Addition/Subtraction]: ![\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%7B%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%7D%20%5C%2C%20dx%20%3D%20%5Cint%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5Cpm%20%5Cint%20%7Bg%28x%29%7D%20%5C%2C%20dx)
U-Substitution
Area of a Region Formula: ![\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Bf%28x%29%20-%20g%28x%29%5D%7D%20%5C%2C%20dx)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Identify</u>
<em>Graph the systems of equations - see attachment.</em>
Top Function: 
Bottom Function: 
Bounds of Integration: [-1.529, 1.718]
<u>Step 3: Integrate Pt. 1</u>
- Substitute in variables [Area of a Region Formula]:

- [Integral] Rewrite [Integration Property - Addition/Subtraction]:

- [Right Integral] Integration Rule [Reverse Power Rule]:

- Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:

<u>Step 4: Integrate Pt. 2</u>
<em>Identify variables for u-substitution.</em>
- Set <em>u</em>:

- [<em>u</em>] Basic Power Rule [Derivative Rule - Addition/Subtraction]:

- [Limits] Switch:

<u>Step 5: Integrate Pt. 3</u>
- [Integral] U-Substitution:

- [Integral] Integration Rule [Reverse Power Rule]:

- Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Answer:
1.Therefore the solution of given system is (3,4)
2.Therefore the solution of given system is (-1,2)
Step-by-step explanation:
1.
Given the system
2x +3y =18...........(1)
-2x+5y =14...........(2)
Adding the equation (1) and (2)
2x+3y-2x+5y= 18+14
⇔8y = 32
⇔
⇔y = 4
Putting the value of y in equation (1)
2x + 3. 4=18
⇔2x+12 =18
⇔2x = 18-12
⇔2x = 6
⇔x =3
Therefore the solution of given system is (3,4)
2.
Given the system
3x +4y = 5..........(a)
2x +7y =12...........(b)
Equation (a) ×2 - equation (b)×3
2(3x+4y)- 3(2x+7y) = 2.5 -12.3
⇔6x + 8y -6x -21y = 10-36
⇔ -13y = -26
⇔
⇔y = 2
Putting the value of y in equation (a)
3x +4.2 =5
⇔3x = 5 -8
⇔3x = -3
⇔x = -1
Therefore the solution of given system is (-1,2)
Answer:2.50
Step-by-step explanation:
So you basically add all the numbers together multiply them by 100& divide by 54