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3 years ago

Can someone help me with this question 2x+3=15 is x

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

Your answer is correct !!!!

djyliett [7]3 years ago

6 0

Answer: x=6

Hope this helps!

Step-by-step explanation:

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Find the volume of a cylinder that has a radius of 5 inches and a height of 3 inches

Over [174]

Answer:

235.5 cubic inches

Step-by-step explanation:

The volume of a cylinder is found using the volume formula $V=\pi r^2h$ .

Substitute h=3 and r = 5.

$V = \pi r^2h\\V = \pi (5^2)(3)\\V=\pi *25*3\\V = 75\pi \\V= 235.5$

6 0

3 years ago

What do you add to 3 4/7 to make 6??

Alla [95]

You'll need to add 2 3/7 to 3 4/7 to make 6.
3 + 2 = 5 4/7 + 3/7 = 7/7 =1
5+1=6

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3 years ago

When is the estimation of products a useful tool?

Nadya [2.5K]

When the numbers are either too big, or you just want a close product. Such as 1370 and 1547. Round to the nearest number then add to the other.

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3 years ago

Write y=-4x^2+8x-1 in vertex form

Wittaler [7]

Answer:

(1,3)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers