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Levart [38]
2 years ago
8

Graph the set. in number line (1, ∞) ∩ (−10, ∞)

Mathematics
1 answer:
svlad2 [7]2 years ago
7 0

See attachment for the graph of the set (1, ∞) ∩ (−10, ∞)

<h3>How to graph the set on a number line?</h3>

The set is given as:

(1, ∞) ∩ (−10, ∞)

The above means that the numbers inclusive in the set are numbers between the following set:

  • (1, ∞): All real numbers greater than 1
  • (−10, ∞): All real numbers greater than -10

The intersection of the above set is (1, ∞)

This means that the set (1, ∞) ∩ (−10, ∞) is a set of all real numbers greater than 1

Having done the above illustration, next we plot the set on a number line

See attachment for the graph of the set (1, ∞) ∩ (−10, ∞)

Read more about number lines at:

brainly.com/question/24644930

#SPJ1

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goldfiish [28.3K]
62\% \ of \ 50= 62\% \times 50=\frac{62}{100} \times 50= \frac{62}{2} \times 1=31

31 is 62% of 50.
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This is worth 18 points to whoever gets it right and also if you do get it right first you'll get voted as brainlyess answrr
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The correct answer is <span>1 and 1/2

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In the diagram, JK || GI. If the ratio of HJ to JG is 3 to 1, then what is the ratio of HK to KI?
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⦁ A sphere is inscribed in a cube with a volume of 27 cm3. What is the volume of the sphere?
lyudmila [28]

Answer:

≈ 14.14 cm³

Step-by-step explanation:

First find the side length of the cube.

V=S³

27=S³

∛27=∛s³

3=S

Then the volume of the sphere.

V=\frac{4}{3} × π(pi) × r³(radius cubed)

V=\frac{4}{3} × π(pi) × (1.5³)

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4 0
3 years ago
The population of a particular type of bacteria is known to triple in 22 days. What is the daily growth rate
Paul [167]

Answer: ∛(3)

Step-by-step explanation:

Suppose that at day 0 the population was A.

at day 3, the population will be: 3*A

at day 6, the population will be 3*(3*A) = A*3^2

then, at day N = 3*n (where n = 0, 1, 2.....) the population will be:

P(N) = A*3^n

Particularly, if we take n = 1/3 we will have:

N = 3*1/3 = 1

This means that this is the first day after the day 0.

P(1) = A*3^(1/3)

(then in day one, the population grow by a factor of 3^(1/3))

N = 2 is when n = 2/3, then:

P(2) = A*3^(2/3)

The quotient between P(2) and P(1) is equal to the growth between day one and day two, this should be the same as the growth between day zero and day one.

A*3^(2/3)/(A*3^(1/3)) = 3^( 2/3 - 1/3) = 3^(1/3)

So we found that the daily growth rate is 3^(1/3) or ∛(3)

3 0
3 years ago
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