Can someone help me please!!!

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7). What are the coordinates of point K" on the

Zanzabum

Answer:

Option C.

Step-by-step explanation:

Consider the complete question is "Triangle JKL is transformed using the rule $R(O,90^\circ)\circ r_{y=-x}(x,y)$ . Point K of the pre-image is at (4, 7). What are the coordinates of point K'' on the final image?".

According to $r_{y=-x}(x,y)$ , we get

$(x,y)\rightarrow (-y,-x)$

According to $R(O,90^\circ)$ , we get

$(x,y)\rightarrow (-y,x)$

The rule $R(O,90^\circ)\circ r_{y=-x}(x,y)$ means first reflection and then rotation.

We need to find the image of K(4,7).

After reflection, we get

$K(4,7)\rightarrow K'(-7,-4)$

After rotation, we get

$K'(-7,-4)\rightarrow K''(4,-7)$

Therefore, the correct option is C.

8 0

3 years ago

Read 2 more answers

David borrowed $30,000 to start a business. Four years later, he repaid the $30,000 along with an interest of $1,260. What was t

torisob [31]

Answer:

1.05%.

Step-by-step explanation:

If an amount of money, P, called the principal, is borrowed for a period of t years at an annual interest rate r, the amount of interest, I, is given by

I=PrtwhereIPrt=interest=principal=rate=time

The following information is given.

IPt=$1,260=$30,000=4 years

Substituting the given information into the simple interest formula and solving for r gives

I1,2601,260=Prt=(30,000)(r)(4)=120,000r

Dividing both sides by 120,000 and then converting to a percent, we have

r=1,260120,000=0.0105=1.05%

Thus, David's annual interest rate was 1.05%.

8 0

3 years ago

Read 2 more answers

When $143 is divided in the ratio 2 : 4 : 5, what is the difference between the largest share and the smallest share?

JulsSmile [24]

Answer:

2x+4x+5x=143 ... 11x=143 ... x=13 ... so 26:52:65 ... largest-smallest=65-26=39

Step-by-step explanation:

4 0

2 years ago

John assignments in value of his car overtime the equation for the line of best fit is approximate as Y represents 2.9 X +17.7 w

ycow [4]

Answer:

For the given equation of the line of best fit, the values that complete the table are as follows

An equation for a line of best fit follows the same guidelines as a linear function where 'y' represents the total (value), 'x' represents time (years), -2.9 is the rate, and 17.7 is the starting value. The table indicates that for any year, there is a given value, but what we are solving for is the predicted value. The residual is the different between the given and predicted values. So, for 'a', we need to solve for the 'y' in our equation by replacing 'x' with '1', multiplying by -2.9 and adding 17.7. This gives us 14.8. For 'b', we simply need to subtract the given and predicted values to get a residual of 0.1. For 'c', we again solve for 'y' by replacing 'x' with '3' in our given equation to get 9. And, for 'd' we subtract the given value of 5 and the predicted value of 6.1 to get 1.1.

answer-

a = 14.8

b = 0.1

c = 9

d = -1.1

5 0

3 years ago

Find the sum Sn below:

Hoochie [10]

We can write <em>S</em> as

$\displaystyle S = \sum_{k=0}^{n-1} (n-k)3^k$

and expand it as

$\displaystyle S = n \sum_{k=0}^{n-1} 3^k - \sum_{k=0}^{n-1} k\cdot3^k$

The first sum is geometric, nothing tricky:

$\displaystyle\sum_{k=0}^{n-1} 3^k = 1 + 3 + 3^2 + \cdots + 3^{n-1} \\\\ \implies 3\sum_{k=0}^{n-1} 3^k = 3 + 3^2 + 3^3 + \cdots + 3^n \\\\ \implies -2\sum_{k=0}^{n-1} 3^k = 1 - 3^n \\\\ \implies \sum_{k=0}^{n-1} 3^k = \frac{3^n-1}2$

For the second sum, you can use the same method employed in another question of yours (24494877) to find

$\displaystyle \sum_{k=0}^{n-1} k\cdot 3^k = \frac{(2n-3)3^n+3}4$

So this sum comes out to

$\displaystyle S = n\cdot\frac{3^n-1}2 - \frac{(2n-3)3^n+3}4 \\\\ S = \frac{2n\cdot3^n-2n - (2n-3)3^n-3}4 \\\\ \boxed{S = \frac{3^{n+1}-2n-3}4}$

7 0

3 years ago