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sergeinik [125]
1 year ago
8

A poster is 15 inches wide by 24 inches tall. A smaller version of the same poster is created using a scale factor of 2/3. What

is the area of the smaller poster
Mathematics
1 answer:
Tamiku [17]1 year ago
3 0

The area of the small poster is 160 inches square

<h3>How to determine the area</h3>

From the information given, we have the poster to take the form of a rectangle

The formula for area of a rectangle is;

Area = length × width

For the smaller poster created using a scale of factor 2/3

Length = 2/ 3 × 24

Length = 16 inches

Width = 2/ 3 × 15

Width = 10 inches

Substitute into the formula

Area = 16 × 10

Area = 160 inches square

Thus, the area of the small poster is 160 inches square

Learn more about area here:

brainly.com/question/14137384

#SPJ1

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No 10 yards equals 360 inches
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3 years ago
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Guys I am going to run out of points. Help with 19?<br> I don't need an explanation.
nasty-shy [4]

Answer:

A.) 20x + 2y = 500

B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.

C.) x-intercept = 25; How many T-shirts they can sell at most

Step-by-step explanation:

2y - 500 = -20x

20x + 2y - 500 = 0

20x + 2y = 500

y-intercept = 250; its meaning is how many boxes of pencils they started with.

20x + 2y = 500

20(0) + 2y = 500

2y = 500

2y/2 = 500/2

y = 250

x-intercept = 25; How many T-shirts they can sell at most

20x + 2y = 500

20x + 2(0) = 500

20x = 500

20x/20 = 500/20

x = 25

4 0
3 years ago
1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0
3 years ago
Please help me with this problem! <br> y =<br><br> 37<br> 39<br> 51
nika2105 [10]

y = arctan(8/10)

y = 38.65

y = 39

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Find the equation of the straight line that passes through points (-1; -2) and (3; 4)
Leya [2.2K]
Y=mx+b is our base equation

m=slope, so let's find that first:
m= change in y/change in x
So between the points (-1,-2) and (3,4),
The y values, -2 and 4, have a difference of 6. The x values, -1 and 3, have a difference of 4. This makes our slope 6/4 (or 3/2 simplified)

Now our equation is
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We still need to find b
To find b, we can substitute a point given to us. Let's use (3,4) just to avoid negatives.

4=3/2(3) + b
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Now let's put it all back together!

Y=3/2x-1/2 Is the answer.

I hope this Helps!


6 0
3 years ago
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