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Lady_Fox [76]
3 years ago
10

Help with math pleasr

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0
To solve this you need to take the answer from the previous iteration.

Iteration 1: The answer is given
a1 = 300

Iteration 2: Solve using the equation. a(n-1) is the answer from the previous iteration. n = the number of the current iteration. So, a(n-1) = 300 and n = 2

a2 = 300/2 = 150

Iteration 3: a(n-1) = 150 and n = 3
a3 = 150/3 = 50

Iteration 4: a(n-1) = 50 and n = 4
a4 = 50/4 = 12.5

Answer: 12.5
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Step-by-step explanation:

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Answer:

  • y = 20
  • 4^8
  • x = 0

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^0 = 1 . . . . for a ≠ 0

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And, it is convenient to know the cubes of small integers:

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1) p^3 × p^5 = p^-12 × p^y

Equating exponents:

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6 0
3 years ago
Read 2 more answers
How much do you need to invest every month in an annuity to
Katen [24]

Answer:

A=25000 is the future value. P the value that we need to invest. r= 0.04 represent the interest rate in fraction. n = 12 represent the number of times that the rate is compounded in a year. t = 5 years.

If we solve for the value of P we got:

P= \frac{A}{(1+ \frac{r}{n})^{nt}}

And replacing we got:

P= \frac{25000}{(1+ \frac{0.04}{12})^{12*5}} =20475.078

And rounded to the nesrest penny we need to invest $20475.08 in order to have after 5 years $25000

Step-by-step explanation:

For this case we can use the future value with compound interest given by:

A = P (1+ \frac{r}{n})^{nt}

Where:

A=25000 is the future value. P the value that we need to invest. r= 0.04 represent the interest rate in fraction. n = 12 represent the number of times that the rate is compounded in a year. t = 5 years.

If we solve for the value of P we got:

P= \frac{A}{(1+ \frac{r}{n})^{nt}}

And replacing we got:

P= \frac{25000}{(1+ \frac{0.04}{12})^{12*5}} =20475.078

And rounded to the nesrest penny we need to invest $20475.08 in order to have after 5 years $25000

8 0
3 years ago
The zeros of the quadratic function described by the graph below is
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7. The zeros of the quadratic function described by the graph below is

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