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horsena [70]
3 years ago
14

The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the

river (Event Z) Grew at most 3 feet during the year (Event E) 10 35 Grew more than 3 feet during the year (Event F) 50 5 If a tree grew more than 3 feet during the year, how much more likely is it that the tree was at most 50 yards from the river? Show all of your work.
Mathematics
1 answer:
Alona [7]3 years ago
4 0

Answer:

It is 91% more likely that the tree was atmost 500 yards from the river.

<h3>Step-by-step explanation:</h3>

We are given with distance and height of 100 young trees near a river.

From that table, in total there are 55 trees which grow more than 3 ft during the year.

And among those 55 trees, 50 trees are atmost 50 yards from river.

Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.

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Answer:

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Step-by-step explanation:

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2 years ago
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Answer:

y=(x+kh)1/h

Step-by-step explanation:

(y-k)h=c

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3 years ago
The results of a common standardized test used in psychology research is designed so that the population mean is 145 and the sta
anygoal [31]

The value 155 is zero standard deviations from the mean, because x = μ , and therefore z = 0.

<h3>What is Standard Deviation?</h3>

The standard deviation is a measure of the amount of variation or dispersion of a set of values.

The key concept we need to manage here is the z-scores , and we can obtain a z-score using the next formula:

z = (x - μ)/σ      ..............[1]

Where

z is the z-score.

x is the raw score: an observation from the normally distributed data that we want standardize using [1].

μ is the population mean.

σ is the population standard deviation.

These standardized values have always the same probability in the standard normal distribution, and this is the advantage of using it for calculating probabilities for normally distributed data.

A subject earns a score of 155.

From the question, we know that:

x = 155.

μ = 155

σ = 50

Having into account all the previous information, we can say that the raw score, x = 155, is zero standard deviations units from the mean. The subject earned a score that equals the population mean. Then, using [1]:

z = (x - μ)/σ

z = (155 - 155) / 50

z = 0/50

z = 0

As we say before, the z-score "tells us" the distance from the population mean, and in this case this value equals zero:  

x = μ

Therefore, z = 0

So, the value 155 is zero standard deviations from the [population] mean.

Learn more about Standard Deviation from:

brainly.com/question/13905583

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8 0
2 years ago
Round each number to the nearest ten and estimate the sum.<br>82.14 + 38.5 + 41.3​
blagie [28]

82.14 will be rounded down to 80, 38.5 will be rounded up to 40, and 41.3 will be rounded down to 40.

80 + 40 + 40 = 160

The approximate sum is 160.

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