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Soloha48 [4]
1 year ago
5

Find the surface area of a pentagon-based pyramid with slant height of 11 m.

Mathematics
1 answer:
Ronch [10]1 year ago
5 0

Answer:

108.75 square meter.

Step-by-step explanation:

<h3>Surface area of pentagon based pyramid:</h3>

   \sf \boxed{\text{\bf Surface area of pentagonal pyramid = $ \bf \dfrac{5}{2}*b*(a + s)$}}

  Here,  b is the base length of the pyramid. b = 3 m

              a is the apothem of the pyramid. a = 3.5 m

              s is the slant height of the pyramid. s = 11 m

     \sf Surface \ area = \dfrac{5}{2}*3*(11 + 3.5)

                         \sf = \dfrac{5}{2}*3*14.5\\\\     = 108.75 \ m^2

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4 years ago
What values of c and d make the equation true? Assume x&gt;0 and 20.
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Answer:

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Step-by-step explanation:

If x>0 and y>0, then

\sqrt{\dfrac{50x^6y^3}{9x^8}}=\sqrt{\dfrac{25\cdot 2y^2\cdot y}{9x^2}}=\dfrac{5y\sqrt{2y}}{3x}.

9x

8

50x

6

y

3

=

9x

2

25⋅2y

2

⋅y

=

3x

5y

2y

.

If

\dfrac{5y\sqrt{2y}}{3x}

3x

5y

2y

is equal to

\dfrac{5y^c\sqrt{2y}}{dx},

dx

5y

c

2y

,

then

\begin{gathered}y=y^c\Rightarrow c=1,\\ \\3x=dx\Rightarrow d=3.\end{gathered}

y=y

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Step-by-step explanation:

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