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Soloha48 [4]
1 year ago
5

Find the surface area of a pentagon-based pyramid with slant height of 11 m.

Mathematics
1 answer:
Ronch [10]1 year ago
5 0

Answer:

108.75 square meter.

Step-by-step explanation:

<h3>Surface area of pentagon based pyramid:</h3>

   \sf \boxed{\text{\bf Surface area of pentagonal pyramid = $ \bf \dfrac{5}{2}*b*(a + s)$}}

  Here,  b is the base length of the pyramid. b = 3 m

              a is the apothem of the pyramid. a = 3.5 m

              s is the slant height of the pyramid. s = 11 m

     \sf Surface \ area = \dfrac{5}{2}*3*(11 + 3.5)

                         \sf = \dfrac{5}{2}*3*14.5\\\\     = 108.75 \ m^2

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Use the two given functions to choose the best statement comparing the graphs to each other.
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If we graph these 2 line on a graphing calculator we can clearly see that Function 2 has been shifted up 9 units.

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The admission prices for a small fair are $1.50 for children and $4.00 for adults. In one day there was $5050 collected. If we k
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Step-by-step explanation:

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The graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of 4, negative 2 What is the
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7 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
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