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amid [387]
2 years ago
10

7-113 b.

Mathematics
1 answer:
Jlenok [28]2 years ago
5 0

An equilateral shape is a shape that has all congruent sides.

<em>Sandy has a greater probability of selecting an equilateral shape</em>

Given

Sandy: <em>Equilateral triangle, Rhombus, and Regular hexagon</em>

Robert: <em>Scalene triangle, Kite, Isosceles trapezoid, Non-special quadrilateral, and Obtuse isosceles triangle</em>

All three shapes in Sandy's shape bucket are equilateral.

So, the probability that Sandy picks an equilateral shape is 1

All five shapes in Robert's shape bucket are non-equilateral.

So, the probability that Robert picks an equilateral shape is 0

By comparing the probabilities:

<em>1 is greater than 0</em>

Hence, Sandy is more likely to pick an equilateral shape than Robert.

Read more about probabilities at:

brainly.com/question/24297863

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ANSWER FAST!! All of the following angle pairs are ALWAYS congruent when a transversal passes through 2 parallel lines EXCEPT:
Murrr4er [49]

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Adjacent angles

Step-by-step explanation:

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3 years ago
9340.00 is invested into an account that earns 8 1/2% simple interest for 15 years. What is the interest earned and what is the
Margarita [4]

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3 years ago
I don't really understand the question so can someone help me answer the question please?​
Ksivusya [100]

Answer:

1/ 3

Step-by-step explanation:

If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:

=> P(E) = number of cards of the required type/ total number of cards

● Total number of spades( ♤ ) = 3

{the queen, one ace and the nine are all spades}

● Total number of cards = 6

Probability of drawing a spade= 3/ 6

= 1/ 2

● Total number of "7" = 1

● Total number of cards = 6

Probability of drawing a 7

= 1/ 6

Now, what's asked is the difference in the probabilities of drawing a spade and a seven.

= 1/ 2 - 1/ 6

= 3/ 6 - 1/ 6

= 2/ 6

= 1/ 3

Hence, 1/ 3 of a greater chance of drawing a spade over a 7.

5 0
3 years ago
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