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3 years ago

7-113 b.

Mathematics

1 answer:

Jlenok [28]3 years ago

5 0

An equilateral shape is a shape that has all congruent sides.

Sandy has a greater probability of selecting an equilateral shape

Given

Sandy: Equilateral triangle, Rhombus, and Regular hexagon

Robert: Scalene triangle, Kite, Isosceles trapezoid, Non-special quadrilateral, and Obtuse isosceles triangle

All three shapes in Sandy's shape bucket are equilateral.

So, the probability that Sandy picks an equilateral shape is 1

All five shapes in Robert's shape bucket are non-equilateral.

So, the probability that Robert picks an equilateral shape is 0

By comparing the probabilities:

1 is greater than 0

Hence, Sandy is more likely to pick an equilateral shape than Robert.

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A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d

Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

3 0

4 years ago

Solve for x: −2(x + 3) = −2x − 6 0 3 All real numbers No solution

Alik [6]

Answer:

x ∈ All real numbers

Step-by-step explanation:

When the distributive property is applied to the left side, the parentheses can be eliminated and the equation becomes ...

-2x -6 = -2x -6

This is true for all possible values of x, "all real numbers".

8 0

3 years ago

Read 2 more answers

Can someone please help me on this question?

solniwko [45]

ANSWER:

According to question, our g(x) becomes f(x) - 5.

When x = 1,

f(x) - 5 = 5 - 5 = 0.

When x = 2,

f(x) - 5 = 7 - 5 = 2.

When x = 3,

f(x) - 5 = 11 - 5 = 6.

When x = 4,

f(x) - 5 = 19 - 5 = 14.

So, Correct choice - [D]

4 0

3 years ago

What is f(x) = x2 – 8x 11 written in vertex form? f(x) = (x – 4)2 – 5 f(x) = (x – 4)2 5 f(x) = (x 4)2 – 27 f(x) = (x 4)2 27?

ioda

Y= (x - 4) ^2 -5 you are welcome :)

3 0

3 years ago

Read 2 more answers

Two ships leave a harbor at the same time. One ship travels on a bearing Upper S 14 degrees Upper W at 15 miles per hour. The ot

jekas [21]

Answer:

69.94 miles

Step-by-step explanation:

The distance d₁ the first ship moves after 3 hours is 3 hours × 15 miles per hours = 45 miles

The distance d₂ the second ship moves after 3 hours is 3 hours × 12 miles per hours = 36 miles.

The angle the first ship's direction makes in the North-East direction is 90° - 75° = 15°

The angle the second ship's direction makes in the South-West direction = 14°

The distance moved by the two ships form the side of a triangle. The angle, θ between the two ship directions is 14° + 90° + 15° = 119°

Using the cosine rule, we find the distance d between the two ships

d = √(d₁² + d₂² -2d₁d₂cosθ)

= √(45² + 36² -2×45×36cos119°)

= √(2025 + 1296- (-1570.78))

= √(3321 + 1570.78)

= √4891.78

= 69.94 miles

4 0

3 years ago